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k0ka [10]
2 years ago
7

A shade of yellow light with a wavelength of 5.8×10-7 m and a frequency of 5.17 × 10-14 Hz

Mathematics
1 answer:
harina [27]2 years ago
4 0

Step-by-step explanation:

We have,

The wavelength of yellow light, \lambda=5.8\times 10^{-7}\ m

Frequency of yellow light, f=5.17\times 10^{-14}\ Hz

It is assumed to find the speed of light in the yellow light.

The speed of a wave is given in terms of wavelength and frequency as :

v=f\lambda\\\\v=5.17\times 10^{-14}\times 5.8\times 10^{-7}\\\\v=2.99\times 10^{-20}\ m/s

So, the speed of light in a shade of yellow light is 2.99\times 10^{-20}\ m/s.

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I'm guessing S^20 is actually referring to the 20th partial sum S_{20}, with

S_{20}=1+(1+1\times0.1)+(1+2\times0.1)+\cdots+(1+18\times0.1)+(1+19\times0.1)

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S_{20}=1+1.1+1.1^2+\cdots+1.1^{18}+1.1^{19}

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(a) Combining like terms, we have

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we end up with

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(b) Multiply S_{20} by 1.1, then subtract this from S_{20}:

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