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amm1812
3 years ago
15

A child is upset because his ice cream is melting. He thinks he now has less dessert. Which of these explanations correctly stat

es why the child is incorrect?
Chemistry
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0
The ice cream melts because it is gaining heat and energy from an endothermic reaction but the mass of the ice cream never leaves the cone. This is because the Law of Conservation of Mass says that matter is not created nor destroyed. Where can the mass go exactly?
Nowhere because it stays in the cone and is the same amount of ice cream as before.
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Initial mass of triphenyl methanol in g = 0.220g Initial volume of 33% HBr solution in ml = 0.60 ml Find mas of triphenyl bromid
tensa zangetsu [6.8K]

Answer:

0.792g of triphenyl bromide are produced.

Explanation:

The reaction of triphenyl methanol with HBr is:

triphenyl methanol + HBr → Triphenyl bromide.

<em>Reaction (1:1), 1 mole of HBr reacts per mole of triphenyl methanol.</em>

<em />

To know the mass of triphenyl bromide assuming a theoretical yield (Yield 100%) we need to find first <em>limiting reactant</em>:

Moles triphenyl methanol (Molar mass: 260.33g/mol) =

0.220g × (1mol / 260.33g) = <em>8.45x10⁻³ moles Triphenyl methanol</em>

Moles HBr (Molar mass: 80.91g/mol; 33%=33g HBr/100mL) =

0.60mL ₓ (33g / 100mL) ₓ (1mol / 80.91g) = <em>2.45x10⁻³ moles HBr</em>

<em />

As amount of moles of HBr is lower than moles of triphenyl methanol, HBr is <em>limiting reactant.</em>

<em />

As HBr is limiting reactant, moles produced of triphenyl bromide = moles HBr = <em>2.45x10⁻³ moles</em>

As molar mass of triphenyl bromide is 323.2g/mol, mass of triphenyl bromide is:

2.45x10⁻³ moles × (323.2g / mol) =

<h3>0.792g of triphenyl bromide are produced.</h3>
5 0
3 years ago
A certain substance, X, decomposes. 75 % of X remains after 100 minutes. How much X remains after 200 minutes if the reaction or
frosja888 [35]
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8 0
3 years ago
A horse pulls a 95 kg sleigh to the top of a snow-covered hill. If the hill is 6.2m high, how much work does the horse do on the
DiKsa [7]
U=mgh=95*9.8*6.2=……using calculator
5 0
3 years ago
How much naoh is needed to prepare 461 ml of solution with a ph of 10.00?
Trava [24]

Answer: -

Volume of NaOH = 461 mL = 461/1000 = 0.461 L

pH = 10.0

Using the relation pH + pOH = 14.00

pOH = 14.00 - 10.00= 4.00

Using the relation

[OH⁻] = 10^{-pOH}

= 10^{-4.00} M

Since NaOH is a monobasic acid,

[NaOH] = [OH⁻] = 10^{-4.00} M

Amount of NaOH = [NaOH] x Volume of NaOH

= 10^{-4.00} M x 0.461 L

= 4.61 x 10⁻⁵ mol

Molar mass of NaOH = 23 x 1 + 16 x 1 + 1 x1

= 40 g / mol

Mass of NaOH required = 4.61 x 10⁻⁵ mol x 40 g/ mol

= 1.84 x 10⁻³ g

3 0
4 years ago
sing any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 25.0°C for the following reaction
prisoha [69]

Answer:

2.76 × 10⁻¹¹  

Explanation:

I don’t have access to the ALEKS Data resource, so I used a different source. The number may be different from yours.

1. Calculate the free energy of formation of CCl₄

                         C(s)+ 2Cl₂(g)→ CCl₄(g)

ΔG°/ mol·L⁻¹:       0         0         -65.3

ΔᵣG° = ΔG°f(products) - ΔG°f(reactants) = -65.3 kJ·mol⁻¹

2. Calculate K

\text{The relationship between $\Delta G^{\circ}$ and K  is}\\\Delta G^{\circ} = -RT \ln K

T = (25.0 + 273.15) K = 298.15 K

\begin{array}{rcl}-65 300 & = & -8.314 \times 298.15 \ln K \\65300& = & 2479 \ln K\\26.34 & = & \ln K\\K& = & e^{26.34}\\&= & \mathbf{2.76 \times 10}^{\mathbf{11}}\\\end{array}

3 0
3 years ago
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