Answer:
KO is the limiting reactant.
0.11 mol O₂ will be produced.
Explanation:
4 KO₂ + 2 H₂O ⇒ 4 KOH + 3 O₂
Find the limiting reagent by dividing the moles of the reactant by the coefficient in the equation.
(0.15 mol KO₂)/4 = 0.0375
(0.10 mol H₂O)/2 = 0.05
KO₂ is the limiting reagent.
The amount of product produced depends on the limiting reagent. To find how much is produced, take moles of limiting reagent and multiply it by the ratio of reagent to product. You can find the ratio by looking at the equation. For every 4 moles of KO₂, 3 moles of O₂ are produced.
0.15 mol KO₂ (3 mol O₂)/(4 mol KO₂) = 0.1125 mol O₂
0.11 mol O are produced.
The correct answer is 9.7 grams because mg are 1,000 difference to grams.
Answer:The maximum kinetic energy KEe of ejected electrons (photoelectrons) is given by KEe=hf−BE KE e = h f − BE , where hf is the photon energy and BE is the binding energy (or work function) of the electron to the particular material.
Explanation:
Correct answer: C) 1.6 g
Molarity is the moles of solute present per liter solution.
The given molarity of the solution is 0.01 M.
Volume of the solution = 1 L
Calculating the moles from molarity and volume:
Converting moles to mass of copper sulfate:
Answer:
violet has a frequency of 668-789 THz :)
Explanation:
