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jarptica [38.1K]
3 years ago
8

Explain why beaches can be considered both erosional and depositional. Remember to write in complete sentences!

Physics
1 answer:
nevsk [136]3 years ago
6 0

Answer:

Waves wash against the shore which can lead to erosion. However, the waves also bring in pebbles and sand particles from the ocean, which is an example of deposition.

Explanation:

That would be my answer

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Paladinen [302]
The answer should be the number, or amount, of cycles that occur in a given time. Frequency is basically Hertz. Frequency is the number of waves that pass through a certain point every second. I hope that I was able to answer your question.
Peace out!

- Hershy103
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3 years ago
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The Earth's Radius is 6.3710x106 m and mass is 5.9742x1024 kg. What is the acceleration due to gravity at Mount Everest (elevati
Shalnov [3]

Answer is

9.773m/s^2

-----------------------------------------------------------------------------

Given,

h=8848m

The value of sea level is 9.08m/s^2. So, Let g′ be the acceleration due to the gravity on Mount Everest.

g′=g(1 − 2h/h)

=9.8(1 - 6400000/17696)

=9.8(1 − 0.00276)

9.8×0.99724

=9.773m/s^2

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hope this helps :)

3 0
2 years ago
What is the moon phase today
Elis [28]
Waxxing Gibbous Phase
4 0
2 years ago
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An object moves along the x axis. The graph shows it’s position x as a function of time t. Find the average velocity of the obje
nadezda [96]
Question is from B to C

Answer: (b) 1.5m/s

x1=3m, x2=9m
t1=1s, t2=5s
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Time elapsed, ∆t=(5-1)s=4s

So average velocity v =∆x/∆t=6/4=1.5m/s
6 0
2 years ago
nert xenon actually forms many compounds, especially with highly electronegative fluorine. The ΔH o f values for xenon difluorid
loris [4]

Answer:

For Xenon fluoride, the average bond energy is 132kj/mol

For tetraflouride,the average bond energy is 150.5kj/mol.

For hexaflouride, the average bond energy is 146.5 kj/mol

Explanation:

For xenon fluoride

105/2 = 52.5

For F-F

159/2 = 79.5

Average bond energy of Xe-F = 79.5 + 52.5 = 132kj/mole

For tetraflouride

284/4 = 71

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159/2 = 79.5

Average bond energy = 79.5 + 71 = 150.5kj/mol

For hexaflouride

402/6 = 67

F-F = 159/2 = 79.5

Average bond energy = 67 + 79.5 = 146.5kj/ mol

3 0
2 years ago
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