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3 years ago

14

The cars salemens tells you that the car can go from a stopped position to 60 miles per hour in 6 seconds he is giving you the c

ars rate of what

1 answer:

Gemiola [76]3 years ago

8 0

The car salesman is giving you the cars rate of acceleration.

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Consult Multiple Concept Example 10 in preparation for this problem. Traveling at a speed of 18.2 m/s, the driver of an automobi

Anettt [7]

Answer:

The speed of the automobile after 1.43s is 10 $\frac{m}{s}$

Explanation:

$a= \frac{-f}{m}= \frac{-u_{k}*m*g}{m}$

$a= -u_{k}*g=- 0.590* 9.8 \frac{m}{s^{2} }= -5.782 \frac{m}{s^{2} }$

$V_{f} = V_{i} + a*t$

$V_{f} = 18.2 \frac{m}{s} - (5.782 \frac{m}{s^{2} }* 1.43 s)$

$V_{f} = 9.93174 \frac{m}{s}$

$V_{f}$ ≅ 10 $\frac{m}{s}$

7 0

3 years ago

A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The

tensa zangetsu [6.8K]

Answer:

Total momentum before collision

P1 =.4 * 3.5 = 1.4 ignoring units here

Total momentum after collision

P2 = .6 * V - .4 * .7 = .6 V - .28

.6 V = 1.4 + .28 momentum before = momentum after

V = 2.8 cm/sec

In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm

5 0

3 years ago

A certain wire, 3 m long, stretches by 1.2 mm when under tension of 200 N. By how much does an equally thick wire 6 m long, made

shusha [124]

Answer:

2.4 mm

Explanation:

Given that:

Initial Original length of the wire L = 3 mm

The stretch of the first wire ΔL= 1. 2 mm

The length of the second wire L'' = 6 mm

The stretch of the second wire ΔL'' = ???

Considering the Tension of the system; the Young modulus and the cross sectional remains constant ; as such:

$\frac{Y}{Y''} = \frac{FL}{A \Delta L} *\frac{A \Delta L''}{FL''}$

$1= \frac{L \Delta L''}{L'' \Delta L}$

$\Delta L''= \frac{L'' \Delta L }{L}$

$\Delta L''= \frac{6 \ m * 1.2 \ mm }{3 \ m}$

$\Delta L''=2.4 \ mm$

Thus, the same material under the same tension stretches 2.4 mm

8 0

3 years ago

Read 2 more answers

A Christmas light is made to flash via the discharge of a capacitor. The effective duration of the flash is 0.25 s (which you ca

Sonbull [250]

Answer:

The correct solution is:

(a) $1.375\times 10^{-2} \ J$

(b) $4.43\times 10^{-3} \ C$

(c) $1.42\times 10^{-3} \ F$

(d) $178.57 \ \Omega$

Explanation:

The given values are:

Effective duration of the flash,

ζ = 0.25 s

Average power,

$P_{avg}=55 \ mW$

$=55\times 10^{-3} \ W$

Average voltage,

$V_{avg}=3.1 \ V$

Now,

(a)

⇒ $E=P_{avg}\times \zeta$

On substituting the values, we get

⇒ $=55\times 10^{-3}\times 0.25$

⇒ $=1.375\times 10^{-2} \ J$

(b)

⇒ $E=Q\times V_{avg}$

then,

⇒ $Q=\frac{E}{V_{avg}}$

On substituting the values, we get

⇒ $=\frac{1.375\times 10^{-2}}{3.1}$

⇒ $=4.43\times 10^{-3} \ C$

(c)

⇒ $C=\frac{Q}{V}$

⇒ $=\frac{4.43\times 10^{-3}}{3.1}$

⇒ $=1.42\times 10^{-3} \ F$

(d)

As we know,

⇒ $R=\frac{1}{4C}$

⇒ $=\frac{1}{4\times 1.42\times 10^{-3}}$

⇒ $=\frac{1000}{5.6}$

⇒ $=178.57 \ \Omega$

5 0

3 years ago

A substance that does not react with metal, has a bitter taste, and turns litmus paper blue is a(n) ___.

Pavlova-9 [17]

The answer to the question is b because acid is a substance that tastes sour, reacts with metal and turns litmus paper blue

5 0

3 years ago