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3 years ago

What is the relationship between atmospheric pressure and the density of gas particles in an area of increasing pressure

Physics

1 answer:

mezya [45]3 years ago

8 0

Answer:

this is a no brainer

Explanation:

As air pressure in an area increases, the density of the gas particles in that area increases.

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Estimate (a) the maximum, and (b) the minimum thermal conductivity values (in W/m-K) for a cermet that contains 83 vol% carbide

velikii [3]

Answer:

k_max = 31.82 w/mk

k_min = 17.70 w/mk

Explanation:

a) the maximum thermal conductivity is given as

$k_{max} = k_m*v_m + k_p*v_p$

where k_m is thermal conductvitiy of metal

k_p is thermal conductvitiy of carbide

v_m = proportion of metal in the cement = 0.17

v_p = proportion of carbide in the cement = 0.83

= 66*0.17 + 28*0.83

k_max = 31.82 w/mk

b) the minimum thermal conductivity is given as

$k_{min} = \frac{k_{carbide}* k_{metal}}{k_{metal} v_{carbide} +k_{metal} v_{carbide}}$

= \frac{28+66}{28*0.17 +66*0.83}

k_min = 17.70 w/mk

7 0

3 years ago

A hovering mosquito is hit by a raindrop that is 45 times as massive and falling at 8.2 m/s , a typical raindrop speed. How fast

netineya [11]

Answer:

The speed of the raindrop and the mosquito is 8.02 m/s.

Explanation:

mass of mosquito = m

mass of drop = 45 m

initial velocity of mosquito, u = 0 m/s

initial velocity of drop, u' = 8.2 m/s

During the inelastic collision, the momentum of the system is conserved.

Let the speed of rain drop and the mosquito is v.

Use the conservation of momentum

m x u + 45 m x u' = (m + 45 m) v

m x 0 + 45 m x 8.2 = 46 m x v

v = 8.02 m/s

7 0

3 years ago

an object with a mass of 7.5 kg accelerates 8.3 m/s2 when an unknown force is applied to it. what is the amount of the force?

nasty-shy [4]

F=MA
F is force
M is mass
A is acceleration
F=MA
F=(7.5 kg)(8.3 m/s^2)
F=62.25 N (newton- SI unit for force)
Hope this helps

5 0

3 years ago

A race car travels on a circular track at an average rate of 125 mi/h. The radius of the track is 0.320 miles. What is the centr

GREYUIT [131]

The centripetal acceleration of the car is 48,800 mi/h2

4 0

3 years ago

A 0.70-kg basketball dropped on a hardwood floor rises back up to 65% of its original height. (a) If the basketball is dropped f

dem82 [27]

Answer:

Part a)

$Loss = 3.6 J$

Part b)

$Loss = 0.99 J$

Part C)

This is loss in terms of thermal energy due to collision with the floor

Explanation:

Part a)

Since we know that the ball rises up by 65% of initial height

so after first bounce it will lose 35% of its initial energy

so we will have

$U = mgH$

Energy Loss = 0.35 mgH[/tex]

$Loss = 0.35(0.70)(9.81)(1.5)$

$Loss = 3.6 J$

Part b)

Energy of the ball after first bounce

$U_1 = 0.65 mgH$

energy of ball after 2nd Bounce

$U_2 = 0.65(0.65 mgH)$

energy of the ball after 3rd bounce

$U_3 = (0.65)(0.65^2)mgH$

$U_3 = 0.65^3(0.70)(9.81)(1.5)$

$U_3 = 2.83 J$

Now we will have energy loss in fourth bounce given as

$Loss = 0.35 U_3$

$Loss = 0.35(2.83)$

$Loss = 0.99 J$

Part C)

This is loss in terms of thermal energy due to collision with the floor

7 0

3 years ago