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lesya692 [45]
3 years ago
6

The water at the top of a waterfall has _____ energy.

Physics
2 answers:
irina [24]3 years ago
6 0
I believe the answer is POTENTIAL ENERGY. The water at the top of the waterfall has Potential Energy. Potential Energy is defined as the energy that is stored when an object is at rest. At the top of the waterfall, water will have maximum potential energy. When the water falls down, it is will already have kinetic energy which is energy that is produced through continuous motion. When it is finally in the bottom, water will have maximum kinetic energy. <span> </span>
coldgirl [10]3 years ago
5 0

Answer:

The water at the top of a waterfall has __potential___ energy.

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What is the current I(3τ), that is, the current after three time constants have passed? The current in the circuit will approach
Olin [163]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

I(\tau)=0.051 A

b

I(3 \tau)=0.076 A

c

I_c= 0.08 A

Explanation:

From the question we are told that

                I(t) = \frac{e}{R}(1-e^{\frac{t}{\tau} }) ; \ Where \ \tau = L/R

From the question we are told to find I(\tau) when t=0  equals the time constant (\tau)

That is to obtain I(\tau).This  is mathematically represented as

                   I(\tau = t)  = \frac{\epsilon}{R} (1- e^{-\frac{\tau}{\tau} })

             Substituting 12 V for \epsilon and 150Ω for R

                     I(\tau) = \frac{12}{150} (1- e^{-1})

                            =0.051 A

From the question we are told to find I(3 \tau) when t=0  equals the 3 times the  time constant (\tau)

That is to obtain I(3\tau).This  is mathematically represented as

                 I(\tau = t)  = \frac{\epsilon}{R} (1- e^{-\frac{3\tau}{\tau} })

                  I(\tau) = \frac{12}{150} (1- e^{-3})

                        =0.076 A

As tends to infinity \frac{\infty}{\tau}  = \infty

So I_c would be mathematically evaluated as

               I_c=I(\infty) = \frac{12}{150} (1- e^{- \infty})

                   = \frac{12}{150}

                   = 0.08 A

5 0
3 years ago
The Lamborghini Huracan has an initial acceleration of 0.80g. Its mass, with a driver, is 1510 kg. If an 80 kg passenger rode al
irina [24]

Answer:

a = 15.1 g

Explanation:

The relation between mass and acceleration is given by :

m\propto \dfrac{1}{a}

If a₁ = 0.80g, m₁ = 1510 kg, m₂ = 80 kg, we need to find a₂

So,

\dfrac{m_1}{m_2}=\dfrac{a_2}{a_1}\\\\a_2=\dfrac{a_1m_1}{m_2}\\\\a_2=\dfrac{0.8g\times 1510}{80}\\\\a_2=15.1g

So, the car's acceleration would be 15.1 g.

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3 years ago
What best describes the angle between a changing electric field and the electromagnetic wave produced by it? (2 points)
Oksanka [162]

A) always equal to a right angle

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3 years ago
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Answer:

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A computer is connected across a 110 V power supply. The computer dissipates 123 W of power in the form of electromagnetic radia
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Answer:

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Explanation:

Resistance is known to provide opposition to the flow of electric current in an electric circuit.

Power dissipated by the computer is expressed as;

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P = IV... (1)

Note that from ohms law, V = IR

I = V/R ... (2)

Substituting equation 2 into 1, we will have;

P = (V/R)×V

P = V²/R.. (3)

Given source voltage = 100V, Power dissipated = 123W

To get resistance R of the computer, we will substitute the given value into equation 3 to have

123 = 100²/R

R = 100²/123

R = 10,000/123

R = 81.3ohms

The resistance of the computer is 81.3ohms

3 0
3 years ago
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