One way is to make into fracitons and simplify
A.5/7=25/35?
yes, true
B. 6/9=18/36?
no
C. 9/18=16/36?
no
D. 35/120=75/250?
no
another way is
if a/b=c/d, then (ad)/(bc)=1 or ad=bc
A is answer
Answer:
$14.12 (after 3 years) and $24.62 (after 5 years)
Step-by-step explanation:
Use the compound amount formula (assuming annual compounding):
A = P(1 + r)^t
Here A = $100(1 + 0.045)^3 (after 3 years)
= $100(1.045)^3 = $114.12.
The interest earned (alone) would be $14.12.
After 5 years:
Here A = $100(1 + 0.045)^5 (after 5 years)
= $100(1.045)^5 = $124.62
The interest earned (alone) would be $24.62.
Option D :
is the area of the kite.
Explanation:
The formula to find the area of the kite is given by
![A=\frac{1}{2} d_{1} d_{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%20d_%7B1%7D%20d_%7B2%7D)
where
and
are the diagonals of the kite.
From the figure, we can determine the lengths of the diagonals
and ![d_2](https://tex.z-dn.net/?f=d_2)
The length of the diagonal
is
![d_1=7 \ in +12 \ in\\d_1=19 \ in](https://tex.z-dn.net/?f=d_1%3D7%20%5C%20in%20%2B12%20%5C%20in%5C%5Cd_1%3D19%20%5C%20in)
The length of the diagonal
is
![d_2=9.5 \ in+9.5 \ in\\d_2=19 \ in](https://tex.z-dn.net/?f=d_2%3D9.5%20%5C%20in%2B9.5%20%5C%20in%5C%5Cd_2%3D19%20%5C%20in)
Thus, the lengths of the diagonals
and
are
and
respectively.
Substituting these values in the formula
, we get,
![A=\frac{1}{2} (19\times19)](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%20%2819%5Ctimes19%29)
![A=\frac{1}{2} (361)](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%20%28361%29)
![A=180.5 \ in^2](https://tex.z-dn.net/?f=A%3D180.5%20%5C%20in%5E2)
Thus, the area of the kite is ![180.5 \ in^2](https://tex.z-dn.net/?f=180.5%20%5C%20in%5E2)
Hence, Option D is the correct answer.
Answer:
y= 8/7x+ 37/7 for the equation that the line passes
<em>Answer:</em>
<em>≈ 44.65(7) m²</em>
<em>Step-by-step explanation:</em>
<em>A = π·r²·80°/360° = 3.14×64×80/360 ≈ 44.65(7) m²</em>