The ball's maximum height is 30.25 feet.
<h3>What is quadratic equation?</h3>
A quadratic equation in math is a second-degree equation of the form ax² + bx + c = 0. Here a, b, are the coefficients, c is the constant term, and x is the variable.
Given:
h= -16t²+36t+10
Differentiate w.r.t. 't',
h' = -32t+36
When h=0, that will be the maximum height
32t= 36
t= 9/8
t= 1.125 sec.
So, The maximum height is
h(1.123)= -16(1.125)² + 36*1.125+10
h(1.125) = 30.25 feet.
Learn more about this concept here:
brainly.com/question/10335037
#SPJ1
Answer: 
Step-by-step explanation:

Hope this helps, have a BLESSED AND WONDERFUL DAY! As well as a great Black History Month and Valentine's day! :-)
- Cutiepatutie ☺❀❤
Answer:
Answer: a5 = 2500
Step-by-step explanation:
For a geometric sequence:
First term = a0
Second term = a1 = a0*r
Third term = a2 = a0*r^2
Fourth term = a3 = a0*r^3
....
nth term = a(n-1) = a0*r^(n-1)
Given: a1 = 4 = a0*r
Also: r = 5
So, a0*5 = 4 => a0 = (4/5)
a5 = a(6-1) = Sixth term = a0*r^5 = (4/5)*5^5 = 2500
Hope this helps
correct me if im wrong☺
Step-by-step explanation:
✓(-1/6×4/7)+(-1/6×-2/5)
✓(-4/42)+(2/30)
✓(-2/21)+(1/15)
✓(-2/21+1/15)
=-<u>1/35</u>
Answer:
2nd term is 8.
nth term is 3n + 2.
Step-by-step explanation:
nth term = 5 + 3(n - 1)
= 3n + 2