The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Answer:
1.41 x 10^-2
Step-by-step explanation:
1.8 x 10^-2 - 3.9 x 10^-33 = 18 x 10^-3 - 3.9 x 10^-3
= (18-3.9) x 10^-3
= 14.1 x 10^-3
= 1.41 x 10^-2
Comment below if you have any questions! If you could mark this answer as the brainliest I would appreciate it!
Answer:
No
Step-by-step explanation:
pi is irrational. That was proven long ago. Unfortunately the proof is harder to understand than the proof that the square root of 2 is irrational, which is accessible to most high school students.
To prove that p is irrational you need to understand calculus, up through integration. Even then, the proof is rather intense and takes careful attention.
Answer:
D.
Step-by-step explanation:
【Look at the image】
Yes the answer is option A
