Answer: Area = 6m²
Smaller number = 16
Hours = 9.6 h
Step-by-step explanation:
A rectangle is 5 meters longer than its width. If the length is shortened by 2 meters and width is increased by 1 meter, the area remains the same. Find the area of the rectangle.
1) w = x m 2) w = x + 1 m
l = x + 5 m l = x + 5 - 2 = x + 3 m
A₁ = A₂
A = w*l
A₁ = x(x+5) = x² + 5x
A₂ = (x+1)(x+2) = x² + x + 2x + 2 = x² + 3x + 2
A₁ = A₂
x² + 5x = x² + 3x + 2
5x - 3x = 2
2x = 2
x = 1
A₁ = x(x+5) = 1.6 = 6 m²
The ratio of two numbers is 2:5. If the larger number is 40, what is the smaller number.
<u> 2 </u> = <u> x </u>
5 40
5x = 80
x = 80/5 = 16
Sixteen construction workers can finish cementing a floor of a building in 3 hours. On a certain day, only 5 construction workers are available for the job. How long will it take the 5 construction workers to do the cementing job?
workers hours
16 3
5 x
↑ ↓ inversely proportional
<u> 5 </u> = <u> 3 </u>
16 x
5x = 16*3
5x = 48
x = 48/5
x = 9.6 h
Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinθ=-3/5 cosecθ=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
Since sinθ=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)
〖BC〗^2=〖AC〗^2-〖AB〗^2
〖BC〗^2=5^2-3^2
〖BC〗^2=25-9
〖BC〗^2=16
BC=4 units
Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosθ=Base/Hypotenuse Cosθ=-4/5
secθ=Hypotnuse/Base secθ=-5/4
tanθ=Perpendicular/Base tanθ=3/4
cotθ=Base/Perpendicular cotθ=4/3
Answer: w= 13
Step-by-step explanation: 8+5 is 13
Answer:
% Po lost = 100[1 - e^(-0.005t)] %; 73.0 g
Step-by-step explanation:
p(t) = 100e^(-0.005t)
Initial amount: p(0) = 100
Amount remaining: p(t) = 100e^(-0.005t)
Amount lost: p(0) – p(t) = 100 - 100e^(-0.005t) = 100[1 - e^(-0.005t)]
% of Po lost = amount lost/initial amount × 100 %
= [1 - e^(-0.005t)] × 100 % = 100[1 - e^(-0.005t)] %
p(63) = 100e^(-0.005 × 63) = 100e^(-0.315) = 100 × 0.730 = 73 g
The mass of polonium remaining after 63 days is 73 g.
