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eimsori [14]
3 years ago
15

if a sample of gas at 25.2 c has a volume of 536mL at 637 torr, what will its volume be if the pressure is increased to 712 torr

?
Chemistry
1 answer:
nignag [31]3 years ago
6 0
Considering ideal gas:
PV= RTn

T= 25.2°C = 298.2 K

P1= 637 torr = 0.8382 atm

V1= 536 mL = 0.536 L

:. R=0.082 atm.L/K.mol

:. n= (P1V1)/(RT) = ((0.8382 atm) x (0.536 L))/
((0.082 atmL/Kmol) x (298.2K))

:. n= O.0184 mol

Then,
P2= 712 torr = 0.936842 atm

V2 = RTn/P2 = [(0.082atmL/
Kmol) x (298.2K) x (0.0184mol) ]/(0.936842atm)

:.V2 = 0.4796 L
OR
V2 = 479.6 ml

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The density of an object is 7 g/mL and has a volume of 2mL, what is the mass of the object?
vladimir2022 [97]

Answer:

Its 14

Explanation:

times 7 n 2 or u can add 7 n 2 and u get 9

3 0
3 years ago
A gaseous mixture at 265K and 1.0 atm contains 25 O2 60 N2 and 15 CO2 mole basis The velocities of the components are 0.084 cm s
Free_Kalibri [48]

Answer:

The molar average velocity is 0.0588 cm/s

The N₂ diffusion velocity relative to the mole average velocity is -0.1428 cm/s

The molar diffusional flux of N₂ is -3.9x10⁻³

Explanation:

Given data:

T = temperature = 265 K

O₂ = 25%

N₂ = 60%

CO₂ = 15%

vO₂ = -0.084 cm/s

vN₂ = 0.12 cm/s

vCO₂ = 0.052 cm/s

The molar average velocity is equal:

v_{av} =(0.25*(-0.084))+(0.6*0.12)+(0.15*0.052)=0.0588cm/s

The N₂ diffusion velocity relative to the molar average velocity is:

v_{i} -v_{av} =-0.084-0.0588=-0.1428cm/s

The molar diffusional flux of N₂ is:

N_{N_{2} } =\frac{P}{RT} y_{A} (v_{i} -v_{av} )=-3.9x10^{-3}

8 0
4 years ago
pH is a logarithmic scale used to indicate the hydrogen ion concentration, [H+], of a solution: pH=−log[H+] Due to the autoioniz
Sophie [7]

Answer:

pH = 2,4

Explanation:

pH is defined as a measure of acidity or alkalinity of a solution based on H⁺ concentration

The HCl dissociates in water thus:

HCl → H⁺ + Cl⁻

That means that moles of HCl are the same than H⁺.

0,35gHCl\frac{1mol}{36,46g} = 9,6x10⁻³ moles HCl ≡ moles H⁺

H⁺ molarity is: \frac{9,6x10^{-3}moles}{2,5L} = 3,84x10⁻³M

As pH = -log [H⁺]

<em>pH = 2,4</em>

I hope it helps!

7 0
3 years ago
The radius of a single atom of a generic element X is 169 picometers (pm) and a crystal of X has a unit cell that is body-center
Virty [35]

The volume of the unit cell is 2.67 x 10⁻²⁸ m³.

<h3>What is the volume of a unit cell of a body-centered cubic crystal?</h3>

In a body-centered cubic unit cell, the volume occupied by the particles of the substance is about 68% of the total unit cell.

Assuming that a single atomic a sphere, the volume is:

Volume(atom) = 4/3 x π x r³

Volume(atom) = 4/3 x π x (169 x 10⁻¹²)³

Volume(atom) = 2.02 x 10⁻²⁹ m³

There are a total of 9 atoms in a body-centered unit cell, so the total volume occupied by atoms is:

2.02 x 10⁻²⁹ x 9

= 1.82 x 10⁻²⁸ m³

Volume of cell = (1.15 x 10⁻²⁸ ) / 0.68

Volume of cell = 2.67 x 10⁻²⁸ m³

Therefore, the volume of the unit cell is 2.67 x 10⁻²⁸ m³.

Learn more volume of unit cells at: brainly.com/question/1594030

#SPJ1

8 0
2 years ago
The recommended daily sugar intake is 50.0 gram. How many moles of sugar (C12H22O11) are in 50.0 grams of sugar?
Kitty [74]

Answer:

0.14607220033346532

Explanation:

3 0
3 years ago
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