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3 years ago

Are the noble gases considered inert or reactive? Why?

Chemistry

1 answer:

mr Goodwill [35]3 years ago

8 0

Answer:

Noble gases are considered as Inert because they are unreactive.

Explanation:

Seven noble elments are known to us , they are: helium, neon, argon, krypton, xenon, radon, and oganesson. Noble gases have 8 electrons in their outermost shell and hence their valence shell is complete, they donot need further electrons to complete their octet so they are unreactive. Also they posses following properties.

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Which of the following accurately represents a carbon source and the process that releases carbon from that source? A. Fossil fu

Andre45 [30]

Option C

Plants, cellular respiration accurately represents a carbon source and the process that releases carbon from that source

<u>Explanation:</u>

Every existing body supplies CO2 off while they evoke power from their food through cellular respiration. Plants and creatures present off CO2 while living and respiring and during lifeless and rotting. Plants are significant carbon sinks, gaining up enormous volumes of CO2 through the manner of photosynthesis.

While plants also discharge CO2 during the means of respiration, the volume of CO2 exercised up by plants by photosynthesis and discharged by exhalation approximately matches out. Volcanic action, forest wildfires, and diverse anthropological exercises deliver carbon.

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3 years ago

One way to measure temperature in some applications is to monitor the gas pressure in a rigid, closed container. What is the tem

julia-pushkina [17]

Answer:

296.43 K is the temperature of a vessel when pressure reads 1.250 atm.

Explanation:

At STP, when pressure is 1.000 atm the value of temperature is 273,15 K.

If the pressure at temperature T reads as 1.250 atm.

$P_1=1.000 atm, T_1=298.15K$

$P_2=1.250 atm,T_2=?$

Applying Gay Lussac's law:

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$ (At constant volume)

$\frac{1.000 atm}{273.15 K}=\frac{1.250 atm}{T_2}$

$T_2=296.43 K$

296.43 K is the temperature of a vessel when pressure reads 1.250 atm.

6 0

3 years ago

What chemical property is most commonly used to classify igneous rocks?

iren2701 [21]

<span>Actually Igneous rocks are classified either based on grain size or based on mineralogy. However grain size is clearly not a chemical property. So we can say that they are classified chemically based on mineralogy or the abundance of quartz or silica present.</span>

7 0

3 years ago

How many lone pairs in TeO2

AlekseyPX

Answer:

0 lone pairs

Explanation:

8 0

3 years ago

I'm stuck on this assignment, +20 PTS and BRAINLIEST for step by step:

dolphi86 [110]

Answer:

2. 2.74 L

3. 488 K

4. 7.47 L

5. 38.6 L

6. 2.85 mol

7. 319 K

8. 3.43 kPa

Explanation:

Generally speaking, you want to convert units to SI units, but in this case, we are working with ratios. This makes up for using the units that wouldn't appropriate elsewhere.

2. Use the equation P₁V₁ = P₂V₂. Solve for V₂.

(3.05 L)(870 kPa) = (969 kPa)(V₂)

V₂ = 2.74 L.

3. Use the equation V₁/T₁ = V₂/T₂. Solve for T₂.

(3.32 L)/(360 K) = (4.50 L)/(T₂)

T₂ = 488 K.

4. Do the same as above, but for V₂.

(5.10 L)/(-56°C) = V₂/(-82°C)

V₂ = 7.47 L

5. Use the equation V₁/n₁ = V₂/n₂. Solve for V₂.

(37.2 L)/(0.750 mol) = (V₂)/(0.778 mol)

V₂ = 38.6 L

6. Do the same as above, but for n₂.

(86.0 L)/(2.65 mol) = (92.5 L)(n₂)

n₂ = 2.85 mol

7. Use the equation P₁/T₁ = P₂/T₂. Solve for T₂.

(3.00 atm)/(390 K) = (2.45 atm)/(T₂)

T₂ = 319 K

8. Do the same as above, but for P₂.

In this specific case, however you will need to convert units. Since both temperatures don't have the same sign, the ratio won't come out right. Convert to Kelvin. Add 273.15 to the temperature in Celsius to convert to Kelvin -12.3°C = 260.85 K 25°C = 298.15 K.

(3.00 kPa)/(260.85 K) = P₂/(298.15 K)

P₂ = 3.43 kPa

There is a lot in here... If you are confused about something, let me know!

6 0

3 years ago