I need help like really bad

Mathematics

2 answers:

serg [7]2 years ago

6 0

Answer:

Step-by-step explanation:

14/15 is less than 7/5

jeyben [28]2 years ago

4 0

Answer:

dang me too I'm like almost failing

You might be interested in

9(x + 1) = 25 + x x = 2 x = 3 x = 4 x = 5

wolverine [178]

Answer:

Step-by-step explanation:

9x + 9 = 25 + x

8x = 16

x = 2

make sure to ask if you need any further guidance.

5 0

1 year ago

Read 2 more answers

I need to solve xy I am so confused please

pychu [463]

Answer:

Step-by-step explanation:

In the question it’s given that : y=|x| => even if x will be a negative number,y will be positive.

1) -3 ; 3 ; (-3,3)

2) -2 ; 2 ; (-2,2)

3) -1 ; 1 ; (-1,1)

4) 0 ; 0 ; (0,0)

5) 1 ; 1 ; (1,1)

6) 2 ; 2 ; (2,2)

7) 3 ; 3 ; (3,3)

8 0

2 years ago

Number 2 I need help on how to solve it

Hunter-Best [27]

Let's simplify the following expression:

$\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}$

We get,

$\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}$ $\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}$