Gas to solid ( a ) is correct i think
Answer: a) Por la estequiometría de la reacción, vemos que: 2. 4. 2. 4. 3. 2. 4. 98 g de H ... a) ¿Qué volumen de ácido sulfúrico concentrado de densidad 1'84 g/mL y 96 ... a) ¿Cuántos moles de átomos de carbono hay en 1'5 moles se sacarosa 12 ... b) El volumen de la misma que debe tomarse para preparar 1 L de disolución de.
The solution is as follows:
Important data:
*0.01 M solution = 0.01 moles <span>disodium ethylenediaminetetraacetate/ L solution
*1 L = 1000 mL
*Molar mass = 372/24 g/mol
Stoichiometric calculation:
0.01 mol/L * (1 L/1000 mL) * 500 mL * </span><span>372.24 g/mol = 1.8612 g
Therefore, you would need 1.8612 grams of </span>disodium ethylenediaminetetraacetate.
Hey there!
Find molar mass of C₆H₂Cl₄.
C: 6 x 12.01
H: 2 x 1.008
Cl: 4 x 35.45
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215.876g
This is the mass of 1 mole of C₆H₂Cl₄.
Multiply 215.876 by 5.99.
215.876 x 5.99 = 1293
The mass of 5.99 moles of C₆H₂Cl₄ is 1293 grams.
Hope this helps!
To determine the mass of the sample in milligrams in this problem, we use the avogadro's number to convert from atoms to moles, relate the moles of element in the sample to the mole present and the molar mass of the sample. We do as follows:
1.552 x 10^22 atoms H ( 1 mol H / 6.022x10^23 atoms H ) ( 1 mol C2H4Cl2 / 4 mol H ) ( 98.96 g C2H4Cl2 / 1 mol C2H4Cl2 ) = 0.625 g C2H4Cl2 = 625 mg <span>C2H4Cl2</span>
