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TEA [102]
3 years ago
14

How many grams of NH3 are needed to provide the same number of molecules as in 0.65 grams of SF6?

Chemistry
1 answer:
Murrr4er [49]3 years ago
7 0
1st --> number of molecules in 0,65g SF₆:

146,1g \ \ \ \rightarrow \ \ \ \ 6,02*10^{23}\\
0,65g \ \ \ \ \rightarrow \ N_{x}\\\\
N_{x}=\frac{0,65g*6,02*10^{23}}{146,1g}\approx0,0268*10^{23}=2,68*10^{21}

2nd --> <span>How many grams of NH3 are needed to provide 2,68</span>ˣ10²¹ molecules


17,03g \ \ \ \ \rightarrow \ \ \ \ 6,02*10^{23}\\&#10;m_{x} \ \ \ \ \ \ \ \ \ \rightarrow \ \ \ \ 2,68*10^{21}\\\\&#10;m_{x}=\frac{2,68*10^{21}*17,03g}{6,02*10^{23}}\approx7,58*10^{-2}=0,0758g
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