In order to solve this question, you use the formula C1V1=C2V2; C1 and V1 represent the concentration and volume of the starting solution respectively, and C2 and V2 represent the concentration and volume of the final solution respectively.
In this case, C1 is 10.5, V1 is unknown, C2 is 0.98 and V2 is 3 liters.
(10.5)(x)=(0.98)(3) (divide both sides by 10.5)
X=0.28 L
This means that you will use 0.28 L of the 10.5 M solution and 2.27 L (3 L-0.28 L) of water to make 3 L of a 0.98 M solution.
Hope this helps
Answer:
See picture below
Explanation:
You are not providing the starting compound. However, I found a similar question so, I will draw the product of this compound, and then, you follow the same procedure.
As the problem states, the diazomethane is often used in reaction with carboxilic acid. This kind of reaction will do an esterification reaction, and the final product will always result in an esther.
So, with the example I give you here, all you have to do is replace the OH in the carboxilic group of your initial compound, for the OCH₃ group.
See picture below.
Hope this helps
<span>One mole of any material contains 6.02 * 10e23 atoms or molecules. This is the Avogadro number.
So 9.25 * 10e24 atoms are contained in (9.25*10e24 / 6.02 * 10e23) = 15.36 moles. So the answer is that moles of C8H18 is 15.36 moles</span>
Explanation:
A gene is the basic physical and functional unit of heredity. Genes are made up of DNA. Every person has two copies of each gene, one inherited from each parent. Most genes are the same in all people, but a small number of genes (less than 1 percent of the total) are slightly different between people. These small differences contribute to each person’s unique physical features.
Answer:- Molar mass of
.
Solution:- It is a stoichiometry problem. Mass of the grill is 30.0 kg and the mass after burning the grill is also 30.0 kg. It means all the charcol is burned and the gas is given off.
2.0 kg of charcol are converted to grams which is 2000 g. Since charcol is pure solid carbon, the grams are divided by the atomic mass of carbon which is 12.
The combustion equation of charcol is written as:

From this balanced equation, there is 1:1 mol ratio between charcol and carbon dioxide. So, the moles of carbon dioxide gas formed are equivalent to the moles of charcol. To convert the moles of carbon dioxide to grams we multiply the moles by it's molar mass.
Carbon dioxide has one carbon and two oxygen atoms so it's molar mass = 12 + 2(16) = 12 + 32 = 44
So, 44 is the molar mass of carbon dioxide and above calculations clearly shows how and where we get this.