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4 years ago

Measuring how quickly a reactant disappears is one way to measure the ______________of the reaction

Chemistry

2 answers:

LUCKY_DIMON [66]4 years ago

5 0

Explanation:

More quickly a reactant will disappear, the more quickly it will result in the formation of products. This means that consumption or disappearance of reactants determines the rate of a reaction because only then products will be formed.

Thus, we can conclude that measuring how quickly a reactant disappears is one way to measure the rate of the reaction.

Ksju [112]4 years ago

5 0

Measuring how quickly a reactant disappears is one way to measure the rate of the reaction. It is because the rate of reaction for product formation and reactants forming is the same. It came to a point where their reaction attains equilibrium.

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The combustion of 135 mg of a hydrocarbon produces 440 mg of CO2 and 135 mg H2O. The molar mass of the hydrocarbon is 270 g/mol.

NeX [460]

Answer:

Molecular formula = C20H30

Explanation:

NB 440mg = 0.44g, 135mg= 0.135g

From the question, moles of CO2= 0.44/44= 0.01mol

Since 1 mol of CO2 contains 1mol of C, it implies mol of C = 0.01

Also from the question, moles of H2O = 0.135/18= 0.0075mole

Since 1 mol of H2O contains 2mol of H, it implies mol of H = 0.0075×2= 0.015 mol of H

To get the empirical formula, divide by smallest number of mole

Mol of C = 0.01/0.01=1

Mol of H = 0.015/0.01= 1.5

Multiply both by 2 to obtain a whole number

Mol of C =1×2 = 2

Mol of H= 1.5×2 = 3

Empirical formula= C2H3

[C2H3] not = 270

[ (2×12) + 3]n = 270

27n = 270

n=10

Molecular formula= [C2H3]10= C20H30

5 0

3 years ago

Which of the following is an example of oxidation? A. Charcoal is placed on a grill and lighting fluid poured over it. B. A car

Vikentia [17]

Answer:

The Answer is (B) A car get rusty over the course of few yearsExplanation:

Explanation:

Oxidation refers to the process of loss of electrons by a molecule,atom or ion during a chemical reaction.The process which is just the opposite of oxidation is reduction,it occurs when their is gain of electrons .
When iron reacts with the oxygen it forms a chemical know as Rust.In this case iron has lost some electrons and the oxygen has gained some electrons

4 0

3 years ago

If 16.00 g of O₂ reacts with 80.00 g NO, how many the excess reactant are left over? (enter only the value, round to whole numbe

pishuonlain [190]

Answer:

Explanation:

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

Mᵣ: 30.01 32.00 46.01

2NO + O₂ ⟶ 2NO₂

Mass/g: 80.00 16.00

2. Calculate the moles of each reactant

$\text{moles of NO} = \text{80.00 g NO} \times \dfrac{\text{1 mol NO}}{\text{30.01 g NO}} = \text{2.666 mol NO}\\\\\text{moles of O}_{2} = \text{16.00 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.5000 mol O}_{2}$