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Sonja [21]
3 years ago
14

Light waves that cross from an air medium to a water medium will

Chemistry
1 answer:
vlada-n [284]3 years ago
5 0
The correct answer would be A.
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Fill in the blanks to complete each statement about the heating of Earth's surface.
Aleonysh [2.5K]

Earth takes in thermal energy from the Sun in a process called thermal radiation.

Sunlight strikes Earth's surface at different angles. This angle is called the angle of insolation.

<h3>What is thermal energy?</h3>

Thermal energy refers to the energy contained within a system that is responsible for its temperature.

Earth takes in thermal energy from the Sun in a process called thermal radiation.

Sunlight strikes Earth's surface at different angles. This angle is called the angle of insolation.

Learn more about thermal energy here:

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1 year ago
What force must act on a 150 kg mass to give it an acceleration of 30 m/s squared? F=ma
Helga [31]

Answer:

its 120

Explanation:

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2 years ago
Calculate the mass percent composition of carbon in C4F8
Anon25 [30]
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4 0
3 years ago
in a simulation mercury removal from industrial wastewater, 0.020 L of 0.10 M sodium sulfide reacts with 0.050 L of 0.010 M merc
Margarita [4]

Answer:  0.1161 grams of mercury(II) sulfide) form.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}     .....(1)

a) Molarity of Na_2S solution = 0.10 M

Volume of solution = 0.020 L

Putting values in equation 1, we get:

0.10M=\frac{\text{Moles of }Na_2S}{0.020L}\\\\\text{Moles of Na_2S}={0.10mol/L\times 0.020}=0.002mol

\text {Moles of}Na_2S=0.10M\times 0.020L=0.002mol

b) Molarity of Hg(NO_3)_2 solution = 0.010 M

Volume of solution = 0.050 L

Putting values in equation 1, we get:

0.010M=\frac{\text{Moles of }Hg(NO_3)_2}{0.050L}\\\\\text{Moles of }Hg(NO_3)_2={0.010mol/L\times 0.050}=0.0005mol

Na_2S+Hg(NO_3)_2\rightarrow HgS+2NaNO_3

According to stoichiometry :

1 mole of Hg(NO_3)_2 reacts with 1 mole of Na_2S

Thus 0.0005 moles of HgNO_3 reacts with=\frac{1}{1}\times 0.0005=0.0005 moles of Hg(NO_3)_2

Thus Hg(NO_3)_2 is the limiting reagent and Na_2S is the excess reagent.

According to stoichiometry :

1 mole of Hg(NO_3)_2 forms=  1 mole of Hg_2S

Thus 0.0005 moles of Hg(NO_3)_2 forms=\frac{1}{1}\times 0.0005=0.0005 moles of Hg_2S

mass of H_2S=moles\times {\text {Molar mass}}=0.0005mol\times 232.2g/mol=0.1161g

Thus 0.1161 grams of mercury(II) sulfide) form.

5 0
3 years ago
An original sample of the radioisotope fluorine-21 had a mass of 80.0 milligrams. Only 20.0 milligrams of this original sample r
lyudmila [28]

<u>Answer:</u> The correct answer is Option 3.

<u>Explanation:</u>

All the radioisotope decay processes follow first order kinetics.

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,  

k = rate constant  = ?

t = time taken for decay process = 8.32 seconds

a = initial amount of the reactant  = 80 mg

a - x = amount left after decay process  = 20 mg

Putting values in above equation, we get:

k=\frac{2.303}{8.32sec}\log\frac{80g}{20}\\\\k=0.166sec^{-1}

The equation used to calculate half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life of the reaction = ?

k = 0.166sec^{-1}

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{0.166sec^{-1}}=4.16sec

Hence, the correct answer is Option 3.

5 0
2 years ago
Read 2 more answers
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