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3 years ago

Please explain bonding of CCl 4

Chemistry

1 answer:

Sati [7]3 years ago

8 0

Answer:

CCl4 is a covalent bonded nonpolar molecule.

Explanation:

Although there is an electronegativity (small) difference between C and Cl, its structure with 4 chlorine atoms allows the polarity to be "canceled out." I have attached a picture of the molecule below where you can clearly see the dipole movement on either side gets canceled hence making it have no net dipole movement. Additionally, CCl4 has a total number of valence electrons to be 32. 7 for one chlorine atom and 4 for a carbon one. The octets are satisfied as well. It's covalent because carbon and chlorine are nonmetals.

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4 years ago

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DanielleElmas [232]

The pH at equivalence point is 12.46

At equivalence point, number of moles of acid, n equals number of moles of base, n'

So, n = n'

CV = C'V' where

C = concentration of acid (HCl) = 0.0470 M,
V = volume of acid = 16.0 mL,
C' = concentration of base (ammonia solution) and
V' = volume of base = 26.0 mL.

<h3>Concentration of ammonia solution</h3>

Making C' subject of the formula, we have

C' = CV/V'

Substituting the values of the variables into the equation, we have

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We know that the ion-product of water Kw is

Kw = [H⁺][OH⁻] = where

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Making [H⁺] subject of the formula, we have

[H⁺} = Kw/[OH⁻]

[H⁺] = 1.01 × 10⁻¹⁴/0.0289

[H⁺] = 34.95 × 10⁻¹⁴

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<h3>pH at equivalence point</h3>

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pH = -㏒[3.495 × 10⁻¹³]

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