4Li + O₂ ⇒ 2Li₂O
Li₂O = 2/4 x 3.33 = 1.665
The final temperature of the mixture in the coffee cup calorimeter is; 19.467 °C
According to the law of energy conservation:
As such; the heat transfer in the liquid water is equal to heat gained by the ice
Heat transfer by liquid water is therefore;
- DH = 6.02 kJ/mol) = 150 × 4.18 × (T1 - T2)
- 6020 J/mol = 627 × (20 - T2)
However, since 18g of water makes one mole
- 6020 J/mol = 6020/18 = 334.44 J/g.
T2 = 19.467°C
Read more on heat:
brainly.com/question/21406849
The answer is physical adaption.
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