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Anastasy [175]
3 years ago
15

A neutral atom of sodium (Na) has an atomic number of 11 and a mass number of 23. How many neutrons would be found in the nucleu

s of this atom of sodium?
Chemistry
1 answer:
SCORPION-xisa [38]3 years ago
7 0
<h3>Answer:</h3>

12 neutrons

<h3>Explanation:</h3>
  • A neutral atom is an atom that has no charge, which means it has no additional electrons or electrons removed from its energy levels.
  • An atom is made up of sub-atomic particles neutrons and protons found in the nucleus and electrons found in the energy levels.
  • The number of protons in the nucleus of a neutral atom is known as the atomic number.
  • In a neutral atom, the atomic number is equal to the number of electrons as protons are equal to the number of electrons.
  • The sum of protons and neutrons in the nucleus of an atom is known as the mass number of an atom.

Therefore;

Protons = Atomic number

Protons + neutrons = Mass number

Thus;

Neutrons = Mass number - protons or

                = Mass number - atomic number

In this case;

Atomic number = 11

Mass number = 23

Thus;

Neutrons = mass number - atomic number

               = 23 - 11

              = 12 neutrons

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Veseljchak [2.6K]

Answer:

your answer would be : examples such as Thallium-206, Lead-210, & Bismuth-214.

7 0
3 years ago
A 200.-milliliter sample of CO2(g) is placed in a sealed, rigid cylinder with a movable piston at 296 K and 101.3 kPa. Determine
bagirrra123 [75]

Answer:

The final volume of the sample of gas V_{2} = 0.000151 m^{3}

Explanation:

Initial volume V_{1} = 200 ml = 0.0002 m^{3}

Initial temperature T_{1} = 296 K

Initial pressure P_{1} = 101.3 K pa

Final temperature T_{2} = 336 K

Final pressure P_{2} =  K pa

Relation between P , V & T is given by

P_{1} \frac{V_{1} }{T_{1} } = P_{2} \frac{V_{2} }{T_{2} }

Put all the values in the above equation we get

101.3 (\frac{0.0002}{296} )= 152 (\frac{V_{2} }{336} )

V_{2} = 0.000151 m^{3}

This is the final volume of the sample of gas.

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4 years ago
Is eubacteria a multicellular organism or a unicellular organism?
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3 years ago
Chemical reaction takes place when iron dust is added into copper sulphate but no reaction takes place when copper dust is added
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3 years ago
What we call "tin cans" are really iron cans coated with a thin layer of tin. The anode is a bar of tin and the cathode is the i
UNO [17]

Answer:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

Explanation:

Although the context is not clear, let's look at the oxidation and reduction processes that will take place in a Fe/Sn system.

The problem states that anode is a bar of thin. Anode is where the process of oxidation takes place. According to the abbreviation 'OILRIG', oxidation is loss, reduction is gain. Since oxidation occurs at anode, this is where loss of electrons takes place. That said, tin loses electrons to become tin cation:

Sn (s)\rightarrow Sn^{2+} (aq) + 2e^-

Similarly, iron is cathode. Cathode is where reduction takes place. Reduction is gain of electrons, this means iron cations gain electrons and produce iron metal:

Fe^{2+} (aq) + 2e^-\rightarrow Fe (s)

The net equation is then:

Sn (s) + Fe^{2+} (aq)\rightarrow Fe (s) + Sn^{2+} (aq)

However, this is not the case, as this is not a spontaneous reaction, as iron metal is more reactive than tin metal, and this is how the coating takes place. This implies that actually anode is iron and cathode is tin:

Actual anode half-equation:

Fe (s)\rightarrow Fe^{2+} (aq) + 2e^-

Actual cathode half-equation:

Sn^{2+} (aq) + 2e^-\rightarrow Sn (s)

Actual net reaction:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

6 0
3 years ago
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