Question

A major component of gasoline is octane (C8H18). When liquid octane is burned in the air it reacts with oxygen gas to produce carbon dioxide gas and water vapor.
Calculate the moles of carbon dioxide produced by the reaction of 0.085 mol of oxygen. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.

Answer 1

Answer:

0.027 moles of carbon dioxide produced by the reaction of 0.085 mol of oxygen.

Explanation:

$2C_8H_{18}+50O_2\rightarrow 16CO_2+18H_2O$

Moles of oxygen gas = 0.085 mol

According to reaction, 50 moles of oxygen gives 16 moles of carbon dioxide gas, then 0.085 moles of oxygen gas will give:

$\frac{16}{50}\times 0.085 mol=0.0272 mol\approx 0.027 mol$ of carbon dioxide

0.027 moles of carbon dioxide produced by the reaction of 0.085 mol of oxygen.