To increase the acceleration of the dog sled, increase the applied force on the sled and reduce the mass on the sled.
According to Newton's second law of motion, the force applied to an object is directly proportional to product of mass and acceleration of the object.
F = ma
where;
<em>a </em><em>is the </em><em>acceleration </em><em>of the dog sled</em>
To increase the acceleration of the dog sled:
- Increase the applied force on the sled.
- Reduce the mass on the sled.
Learn more about Newton's second law here: brainly.com/question/3999427
Answer:
las plantas
Explanation:
Las plantas son los seres vivos capaces de transformar energía luminosa utilizando agua y dióxido de carbono (CO₂) en energía química en forma de moléculas llamadas carbohidratos. El proceso a través del cual realizan esto se denomina fotosíntesis, y para ello requieren un pigmento de color verde denominado clorofila, el cual es necesario para captar la energía luminosa proveniente del Sol.
Answer: Tfinal = 7.1°C
Explanation:
heat released or absorbed = mass × specific heat capacity × change in temperature
q = m × cg × ΔT (eqn 1)
Note: ΔT = (Tfinal - Tinitial)
(q = ? ΔHsoln=25.7kJ/mole = 25700J/mole; mass of solution, m = 100 + 35g = 135g; cg = specific heat capacity of water = 4.18 J°C-1g-1; ΔT = ? masss of solute, NH4NO3 = 35g, molar mass of solute, NH4NO3 = 80g)
molar enthalpy of solution, ΔHsoln
<em> = heat absorbed or released ÷ moles of solute, </em><em>n</em>
ΔHsoln = q ÷ n
q = ΔHsoln × n
<em>moles solute</em>, n = mass solute (g) ÷ molar mass solute (g mol-1)
moles of solute, n = 35g/80g/mol = 0.4375 moles
q = 25700J/mol × 0.4375 mol = 11243.75J
From equation 1 above, ΔT = q / (m × cg) = 11243.75J / (135 × 4.18 J°C-1g-1) = 19.9°C
Since the reaction is endothermic, Tinitial > Tfinal, therefore, Tfinal = Tinitial - ΔT = 27 - 19.9 = 7.1°C
Answer:
An alkyl halide can undergo SN2 reaction with an amine
Explanation:
The displacement of a bromine atom by an an amine (step 2---> 3) in the reaction sequence is an example of an SN2 reaction in which the amine is the nucleophile.
The nitrogen atom of the amine which bears a lone pair of electrons functions as the nucleophile and attacks the electrophilic carbon atom of the alkyl halide displacing the bromide and creating a new Carbon-Nitrogen bond. An ammonium intermediate is immediately formed and the reaction is completed by the abstraction of a hydrogen by a base (such as excess amine present in the system).
This reaction is slower with t-BuNH2 because of steric hindrance and steric crowding in the transition state. SN2 reactions are faster with methylamine where the alkyl carbon is easily accessible.
The detailed mechanism of this reaction has been attached to this answer.
Answer:
68.83 g HgS
Explanation:
The balanced reaction is:
Hg(C₂H₃O₂)₂ + Na₂S ---> 2 NaC₂H₃O₂ + HgS
Because Hg(C₂H₃O₂)₂ reacts completely, it is the limiting reactant. The solid precipitate is mercury (II) sulfide.
To find the amount of solid precipitate, you need to (1) convert grams Hg(C₂H₃O₂)₂ to moles Hg(C₂H₃O₂)₂ (via molar mass from periodic table), then (2) convert moles Hg(C₂H₃O₂)₂ to moles HgS (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles HgS to grams HgS (via molar mass from periodic table).
It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The desired unit should be the numerator. The final answer should have 4 sig figs because the given value with the lowest sig fig value (94.28 grams) has 4 sig figs.
Molar Mass (Hg(C₂H₃O₂)₂): 200.59 g/mol + 4(12.01 g/mol) + 6(1.008 g/mol) + 4(16.00 g/mol)
Molar Mass (Hg(C₂H₃O₂)₂): 318.678 g/mol
Molar Mass (HgS): 200.59 g/mol + 32.07 g/mol
Molar Mass (HgS): 232.66 g/mol
94.28 g Hg(C₂H₃O₂)₂ 1 mole 1 mole HgS 232.66 g
------------------------------- x ------------------ x ------------------------------ x ---------------- =
318.678 g 1 mole Hg(C₂H₃O₂)₂ 1 mole
= 68.83 g HgS
