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avanturin [10]
3 years ago
12

You are given two unknown solutions, A and B. One of the solutions contains water and table salt, and the other contains water a

nd table sugar. Without any testing, using the data table and your knowledge of chemical bonds, you are able to determine which solution contains sugar and which contains salt. Which solution is which? A) A contains sugar and B contains salt, because salt is ionic and a good conductor of electricity. B) A contains salt and B contains sugar, because sugar is ionic and is a good conductor of electricity. C) A contains salt and B contains sugar, because salt is covalent and is poor conductor of electricity. D) A contains sugar and B contains salt, because sugar is covalent and is a good conductor of electricity.
Chemistry
2 answers:
s2008m [1.1K]3 years ago
7 0
It would be <span>A: A contains sugar and B contains salt, because salt is ionic and a good conductor of electricity.</span>
Lelechka [254]3 years ago
5 0

The answer is: A) A contains sugar and B contains salt, because salt is ionic and a good conductor of electricity.

Ionic compounds conduct electricity, because it dissociate in ions and ions conduct electicity.

Ionic substances dissociate in water on cations and anions.

For example, dissociation of sodium chloride in water: NaCl(aq) → Na⁺(aq) + Cl⁻(aq).

Ionic compounds (most of the salts, strong acids and bases) dissolve in water because an ion-dipole interactions.

An ion-dipole is electrostatic interaction between a charged ion (cations and anions) and a molecule that has a dipole (in this example water).  

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miskamm [114]

Answer:

A) 0.95 mol

Explanation:

We will assume the gas given off in the fermentation is an ideal gas because that allows us to use the ideal gas equation.

PV  = nRT

First let's convert all measurements to units that we can use

P = 702 mmHg * 1 atm/760 mmHg = 0.92368 atm

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R = 0.08206 L-atm/mol-K

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0.92368 atm * 25.0 L = n * 0.08206 L-atm/mol-K * 295.65 K

                                  n = 0.9518 mol

4 0
3 years ago
How many half-lives will pass by the time 1.56% of I-131 is present? B. Approximately how many days does that equal? *
serg [7]

Answer: Hmmmmm that's crazy....

There are a couple of equations one could use for this type of problem, but I find the following to be the easiest to use and to understand.

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In this problem, we need to find n and are given the FR, which is 1.56% or 0.0156 (as a fraction).

0.0156 = 0.5n

log 0.0156 = n log 0.5

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n = 6.0 half lives have elapsed

Explanation:

Just wanted to help. Hopefully it's correct wouldn't want to waster your time ;)

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Nataly_w [17]
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kvasek [131]

Answer:

B

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Why are the wind speeds on gas giant planets so much greater than the wind speeds on earth?
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