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avanturin [10]
3 years ago
12

You are given two unknown solutions, A and B. One of the solutions contains water and table salt, and the other contains water a

nd table sugar. Without any testing, using the data table and your knowledge of chemical bonds, you are able to determine which solution contains sugar and which contains salt. Which solution is which? A) A contains sugar and B contains salt, because salt is ionic and a good conductor of electricity. B) A contains salt and B contains sugar, because sugar is ionic and is a good conductor of electricity. C) A contains salt and B contains sugar, because salt is covalent and is poor conductor of electricity. D) A contains sugar and B contains salt, because sugar is covalent and is a good conductor of electricity.
Chemistry
2 answers:
s2008m [1.1K]3 years ago
7 0
It would be <span>A: A contains sugar and B contains salt, because salt is ionic and a good conductor of electricity.</span>
Lelechka [254]3 years ago
5 0

The answer is: A) A contains sugar and B contains salt, because salt is ionic and a good conductor of electricity.

Ionic compounds conduct electricity, because it dissociate in ions and ions conduct electicity.

Ionic substances dissociate in water on cations and anions.

For example, dissociation of sodium chloride in water: NaCl(aq) → Na⁺(aq) + Cl⁻(aq).

Ionic compounds (most of the salts, strong acids and bases) dissolve in water because an ion-dipole interactions.

An ion-dipole is electrostatic interaction between a charged ion (cations and anions) and a molecule that has a dipole (in this example water).  

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Explanation:

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Which of the following questions is outside the scope of science?
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A. How religion and philosophy different
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4 0
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Is salt a iconically bounded compound?
zvonat [6]

Answer:

i believe u mean "ionically". Yes it is.

Explanation:

3 0
2 years ago
Calculate the mass of Octane needed to release 6.20 mol Co2
n200080 [17]
The combustion reaction of octane is as follow,

                           C₈H₁₈  +  25/2 O₂     →     8 CO₂  +  9 H₂O

According to balance equation,

8 moles of CO₂ are released when  =  114.23 g (1 mole) Octane is reacted

So,

      6.20 moles of CO₂ will release when  =  X g of Octane is reacted

Solving for X,
                                     X  =  (114.23 g × 6.20 mol) ÷ 8 mol

                                     X  =  88.52 g of Octane
Result:
           88.52 g of Octane is needed to release 6.20 mol CO₂.
8 0
2 years ago
An oily liquid with a cheesy, waxy odor like that of goats or other barnyard animals is caproic acid, a compound containing carb
Zinaida [17]

The empirical formula for the caproic acid, given the combustion analysis data is C₃H₆O

We'll begin bey obtaining the mass of carbon, hydrogen and oxygen in the compound. This is illustrated below:

How to determine the mass of C

  • Mass of CO₂ = 9.78 g
  • Molar mass of CO₂ = 44 g/mol
  • Molar of C = 12 g/mol
  • Mass of C =?

Mass of C = (12 / 44) × 9.78

Mass of C = 2.67 g

How to determine the mass of H

  • Mass of H₂O = 20.99 g
  • Molar mass of H₂O = 18 g/mol
  • Molar of H = 2 × 1 = 2 g/mol
  • Mass of H =?

Mass of H = (2 / 18) × 4

Mass of H = 0.44 g

How to determine the mass of O

  • Mass of compound = 4.30 g
  • Mass of C = 2.67 g
  • Mass of H = 0.44 g
  • Mass of O =?

Mass of O = (mass of compound) – (mass of C + mass of H)

Mass of O = 4.30 – (2.67 + 0.44)

Mass of O = 1.19 g

<h3>How to determine the empirical formula </h3>

The empirical formula of the compound can be obtained as follow:

  • C = 2.67 g
  • H = 0.44 g
  • O = 1.19 g
  • Empirical formula =?

Divide by their molar mass

C = 2.67 / 12 = 0.2225

H = 0.44 / 1 = 0.44

O = 1.19 / 16 = 0.074

Divide by the smallest

C = 0.2225 / 0.074 = 3

H = 0.44 / 0.0744 = 6

O = 0.074 / 0.074 = 1

Thus, the empirical formula of the compound is C₃H₆O

Learn more about empirical formula:

brainly.com/question/9459553

#SPJ1

6 0
1 year ago
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