Answer:
true
Step-by-step explanation:
true
Answer:
Step-by-step explanation:
![6k^3+10k^2-56k\\2k(3k^2+5k-28)\\=2k[3k^2+12k-7k-28]\\=2k[3k(k+4)-7(k+4)]\\=2k(k+4)(3k-7)](https://tex.z-dn.net/?f=6k%5E3%2B10k%5E2-56k%5C%5C2k%283k%5E2%2B5k-28%29%5C%5C%3D2k%5B3k%5E2%2B12k-7k-28%5D%5C%5C%3D2k%5B3k%28k%2B4%29-7%28k%2B4%29%5D%5C%5C%3D2k%28k%2B4%29%283k-7%29)
common factor is 3k-7
Answer:
Question 2.) 16
144÷9=16
Question 3.) 16
16÷12=1.33... and all the others equal 1.33... as well
Question 4.) 20
20÷16=1.25 and all tho others equal 1.25 as well
Question 5.)12
8÷12=0.66... and all the others equal 0.66.... as well
I hope this is good enough for you: