Answer:
(4, 3)
Step-by-step explanation:
Since, A (-4, 3) is reflected across the y-axis to obtain point B.
Therefore, y coordinate remains the same, x coordinate flips over the y axis to be positive.
(-4,3) ==>> (4,3)
Let the number of cards Aaron has : A
Given :
⊕ Bonny has twice as many cards as Aaron
⊕ Connor has 6 cards more than Bonny
⊕ Total cards : 101
⇒ Number of cards Bonny has : 2A
⇒ Number of cards Connor has : 2A + 6
⇒ Aaron cards + Bonny cards + Connor cards = 101
⇒ A + 2A + 2A + 6 = 101
⇒ 5A = 101 - 6
⇒ 5A = 95
⇒ A = 19
<u>Answer</u> : Aaron has 19 Cards
Answer:
87.97 or 88
Step-by-step explanation:
Well, we can substitute the variables and get :
9(21)+3(3)(21)+12
Then we simplify :
189+189+12
To get :
390 flowers
By the way you might be confused like I was for it said "a cake topping," whilst I assumed all tables had cake toppings which is untrue and I nearly ended up with 630 flowers.
Answer: 0.9649
Step-by-step explanation:
Let A denote the event that the days are cloudy and B denotes the event that the days are rainy.
Given : For the month of March in a certain city, the probability that days are cloudy :
Also in the month of March in the same city,, the probability that the days are cloudy and rainy :
Now by using the conditional probability, the probability that a randomly selected day in March will be rainy if it is cloudy will be :-
![\Rightarrow\ P(B|A)=\dfrac{0.55}{0.57}\\\\=0.964912280702\approx0.9649\ \ \text{[Rounded to four decimal places.]}](https://tex.z-dn.net/?f=%5CRightarrow%5C%20P%28B%7CA%29%3D%5Cdfrac%7B0.55%7D%7B0.57%7D%5C%5C%5C%5C%3D0.964912280702%5Capprox0.9649%5C%20%5C%20%5Ctext%7B%5BRounded%20to%20four%20decimal%20places.%5D%7D)
Hence, the probability that a randomly selected day in March will be rainy if it is cloudy = 0.9649
