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Dmitry_Shevchenko [17]
3 years ago
5

If A is the center of the plate, what is the segment AB called

Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
6 0
Well, is A is the center of the plate, I am going to assume that B is on the end of the plate. So the answer I believe you are looking for is radius.
hammer [34]3 years ago
3 0
Segment AB is the radius
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49/100 in simply that is your answer
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What is the factor of 28/88
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The factors are:
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The product of a number and four, increased by one, is at least 7.
faust18 [17]

Answer:

4/6

Step-by-step explanation:

a number which means "x" or u can name any variable u want

so the product of a number and four means

X×4

the increased by one or plus one

X×4+1

is at least 7

X(4)+1=7

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3 years ago
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Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer
Mumz [18]

Answer:

C) Both

Step-by-step explanation:

The given equation is:

0=(3x+2)(x-4)

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.

Using this property:

(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply (3x+2)(x-4) i.e. 3x^2-12x+2x-8 = 3x^2-10x-8

So, the equation becomes:

0=3x^2-10x-8

Comparing this equation to standard quadratic equation:

ax^2+bx+c=0

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}

The answer is same from both the approaches.

So, the correct answer is:

C) Both

3 0
3 years ago
Can someone help me with a b and c please
abruzzese [7]

Answer:

c.in this 2014,396.12million pets were owned

3 0
3 years ago
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