PLEASE HELP ME WITH QUESTION #7 !!!! PLEASE!!!!! 20 POINTS!!!

Mathematics

1 answer:

pashok25 [27]2 years ago

5 0

let x = total charge

Jane = X=5 + 0.10m

Joe = x=4+0.20m

You might be interested in

Whats the perimeter and area of this shape?

stich3 [128]

Answer:

Step-by-step explanation:

5x12 for the rectangle on the right, then for the circle, using the formula A=πr², I get 28.27, which you divide by 2 because you only need half of the circle, and you get 88.27. I calculated the radius by subtracting 12-6 and then dividing that in half because the radius is half of the distance to the other end of the circle. Then you get the radius of 3, then plug it into the formula to get π(3)², which is just 3.14(9), and you get 28.27.

8 0

2 years ago

Read 2 more answers

Emily is saving $300 a month for a $9,000 down payment on a new car. she will have her down payment total in 18 months. she got

Burka [1]

It would fewer her months by 10

4 0

3 years ago

Read 2 more answers

Assume that f is continuous on [-4,4] and differentiable on (-4,4). The table gives some values of f'(x) x: -4, -3, -2, -1, 0, 1

kondaur [170]

$f$ will be increasing on the intervals where $f'(x)>0$ and decreasing wherever $f'(x)$ . Local extrema occur when $f'(x)=0$ and the sign of $f'(x)$ changes to either side of that point.

$f'(x)$ is positive when $x$ is between -4 and some number between -2 and -1, and also 2 (exclusive) and 4, so you can estimate that $f(x)$ is increasing on the intervals [-4, -2] and (2, 4].

$f'(x)$ is negative when $x$ is between some number between -2 and -1, up to some number less than 2. So $f(x)$ is decreasing on the interval [-1, 1].

You then have two possible cases for extrema occurring. The sign of $f'(x)$ changes for some $x$ between -2 and -1, and again to either side of $x=2$ .