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3 years ago

The graph below shows the amount of money that a student has in the bank at the end of each week.

Mathematics

1 answer:

storchak [24]3 years ago

7 0

Answer:

The student will have 130 dollars in the bank at the end of week 11.

Step-by-step explanation:

Pattern:

The pattern given by this graphic is that:

For each passing week, the student will have $10 more in the bank than at the end of the previous week. So, following this pattern:

At the end of 6 weeks, he will have $80.

At the end of 7 weeks, he will have $90.

At the end of 8 weeks, he will have $100.

At the end of 9 weeks, he will have $110.

At the end of 10 weeks, he will have $120.

At the end of 11 weeks, he will have $130.

The student will have 130 dollars in the bank at the end of week 11.

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3 years ago

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

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1 year ago

In a 30-60-90 triangle, the length of the long leg is 8. Find the length of the hypotenuse.

fiasKO [112]

Answer:

Step-by-step explanation:

In a 30-60-90 triangle, the ratio of the lengths of the angles' opposite sides are <em>1-√3-2</em>.

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Therefore, the hypotenuse, which is <em>double the short leg</em>, is 16√3/3.

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3 years ago