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g100num [7]
3 years ago
8

Consider this polynomial equation

Mathematics
1 answer:
bazaltina [42]3 years ago
3 0

Answer:

2 solutions

-1 and 3 is the real solutions

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A product tester measures four different sizes of shampoo bottles to see if they are filled accurately. The table shows the resu
yarga [219]

By comparing the percent error in all sample, the sample with least percent error is sample 2

Step-by-step explanation:

Percent error is calculated using the formula:

Percent\ Error = \frac{|Approx\ Value- Exact\ Value|}{Exact\ Value}*100

The percent error in each sample needs to be calculated to find the bottle with least percent error

<u>Percent Error for Sample 1:</u>

Amount on bottle = 14 ounces

Actual amount in bottle = 13.7 ounces

Putting the values in the formula

Percent\ Error = E_1 = \frac{|13.7-14|}{14}*100\\= \frac{|-0.3|}{14}*100\\= \frac{0.3}{14}*100\\=0.214*100\\=2.14\%

<u>Percent Error for Sample 2:</u>

Amount on bottle = 24 ounces

Actual amount in bottle = 24.4 ounces

Putting the values in the formula

Percent\ Error = E_2 = \frac{|24.4-24|}{24}*100\\= \frac{|0.4|}{24}*100\\= \frac{0.4}{24}*100\\=0.0166*100\\=1.66\%

<u>Percent Error for Sample 3:</u>

Amount on bottle = 25 ounces

Actual amount in bottle = 25.8 ounces

Putting the values in the formula

Percent\ Error = E_3 = \frac{|25.8-25|}{25}*100\\= \frac{|0.8|}{25}*100\\= \frac{0.8}{25}*100\\=0.032*100\\=3.2\%

<u>Percent Error for Sample 4:</u>

Amount on bottle = 39 ounces

Actual amount in bottle = 40.2 ounces

Putting the values in the formula

Percent\ Error = E_4 = \frac{|40.2-39|}{39}*100\\= \frac{|1.2|}{39}*100\\= \frac{1.2}{39}*100\\=0.307*100\\=3.07\%

By comparing the percent error in all sample, the sample with least percent error is sample 2

Keywords: Samples, Percent errors

Learn more about samples and errors at:

  • brainly.com/question/909731
  • brainly.com/question/902892

#LearnwithBrainly

5 0
4 years ago
Complete parts a through f below to find nonnegative numbers x and y that satisfy the given requirements. Give the optimum value
MArishka [77]

Answer:

  • y = 81-x
  • the domain of P(x) is [0, 81]
  • P is maximized at (x, y) = (54, 27)

Step-by-step explanation:

<u>Given</u>

  • x plus y equals 81
  • x and y are non-negative

<u>Find</u>

  • P equals x squared y is maximized

<u>Solution</u>

a. Solve x plus y equals 81 for y.

  y equals 81 minus x

__

b. Substitute the result from part a into the equation P equals x squared y for the variable that is to be maximized.

  P equals x squared left parenthesis 81 minus x right parenthesis

__

c. Find the domain of the function P found in part b.

  left bracket 0 comma 81 right bracket

__

d. Find dP/dx. Solve the equation dP/dx = 0.

  P = 81x² -x³

  dP/dx = 162x -3x² = 3x(54 -x) = 0

The zero product rule tells us the solutions to this equation are x=0 and x=54, the values of x that make the factors be zero. x=0 is an extraneous solution for this problem so ...

  P is maximized at (x, y) = (54, 27).

7 0
3 years ago
Mangoes are priced 4 for $4.80 how much for one mango?​
omeli [17]

Answer:

one dollar and 20 cents

Step-by-step explanation:

I divided 4.80 by four

4 0
3 years ago
Read 2 more answers
an item that was selling for $1,102 is reduced to $806 to the nearest whole what is the percentage decrease
lakkis [162]

Answer:

26.8602541%

Step-by-step explanation:

1102-806=296

296/1102=.268602541

.268602541*100=

26.8602541%

5 0
4 years ago
Read 2 more answers
Ten times an integer is added to seven times it’s square. If the result is 152, what was the original number?
Bess [88]

Answer:

Required number is 4.

Step-by-step explanation:

Let the required number be a.

Given,

Sum of ten times the integer and seven times it’s square is 152.

= > Ten times of a + seven times of it's square = 152

= > 10( a ) + 7( a )^2 = 152

= > 10a + 7a^2 - 152 = 0

= > 7a^2 + 10a - 152 = 0

= > 7a^2 + ( 38 - 28 )a - 152 = 0

= > 7a^2 + 38a - 28a - 152 = 0

= > a( 7a + 38 ) - 4( 7a + 38 ) = 0

= > ( a - 4 )( 7a + 38 ) = 0

= > a = 4 or - 38 / 7

Hence the required number is 4.

3 0
3 years ago
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