Answer: Choice C
Graph with filled in circles at d = 0 and d = 2, shading in between
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Explanation:
d = amount downloaded in gigabytes
The smallest amount is d = 0. We cannot download a negative amount of data, so this is why d = 0 is the smallest.
The largest amount allowed is d = 2. This is the cap that the ISP has set up.
So basically d can be anything between d = 0 and d = 2, including both endpoints. This means
We use filled in circles for both endpoints to show to the reader "include these endpoints". Shading is done in between to show the entire solution set of possible d values. For instance d = 1 is in that region so it is possible to have this solution. Something like d = 4 is outside the region and not possible.
Answer:
$6.50 per bag of popcorn
Step-by-step explanation:
let a bag of popcorn be represented by p and a candy bar be b
28p + 40b= $282
17p + 20b= $160.50
this is an example of stimatanelous equations
so you have to double the second equation to give 34p + 40b =$321
subtract the equations to give one
6p =$39
divide $39 by 6 to give the value of one bag of popcorn = $6.50
Answer:
2x^3 - 2x^2 - 12x
Step-by-step explanation:
2x(x - 3)(x + 2)
= 2x ( x^2 + 2x -3x - 6)
= 2x (x^2 - x - 6)
= 2x^3 - 2x^2 - 12x (answer).
Answer:
The rate at which the distance from the plane to the station is increasing is 331 miles per hour.
Step-by-step explanation:
We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:
a: is one side of the triangle = altitude of the plane = 3 miles
b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles
h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles
First, we need to find b:
(1)
Now, to find the rate we need to find the derivative of equation (1) with respect to time:
Since "da/dt" is constant (the altitude of the plane does not change with time), we have:
And knowing that the plane is moving at a speed of 500 mi/h (db/dt):
Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.
I hope it helps you!
