Answer:
the remaining money is $1189.22
Step-by-step explanation:
Answer:
We fail to reject H0; Hence, we conclude that there is no significant evidence that the mean amount of water per gallon is different from 1.0 gallon
Pvalue = - 2
(0.98626 ; 1.00174)
Since, 1.0 exist within the confidence interval, then we can conclude that mean amount of water per gallon is 1.0 gallon.
Step-by-step explanation:
H0 : μ= 1
H1 : μ < 1
The test statistic :
(xbar - μ) / (s / sqrt(n))
(0.994 - 1) / (0.03/sqrt(100))
-0.006 / 0.003
= - 2
The Pvalue :
Pvalue form Test statistic :
P(Z < - 2) = 0.02275
At α = 0.01
Pvalue > 0.01 ; Hence, we fail to reject H0.
The confidence interval :
Xbar ± Margin of error
Margin of Error = Zcritical * s/sqrt(n)
Zcritical at 99% confidence level = 2.58
Margin of Error = 2.58 * 0.03/sqrt(100) = 0.00774
Confidence interval :
0.994 ± 0.00774
Lower boundary = (0.994 - 0.00774) = 0.98626
Upper boundary = (0.994 + 0.00774) = 1.00174
(0.98626 ; 1.00174)
Answer:
38,660
Step-by-step explanation:
54 thousands 6 hundreds 12 tens – 15 thousands 8 hundreds 26 tens
54 thousands = 54000
6 hundreds = 600
12 ten = 12*10 = 120
54 thousands 6 hundreds 12 tens = 54000+600+120 = 54720
15 thousands = 15000
8 hundreds = 800
26 tens = 26*10 = 260
15 thousands 8 hundreds 26 tens = 15000+800+260 = 16060
Thus,
54 thousands 6 hundreds 12 tens – 15 thousands 8 hundreds 26 tens
= 54720- 16060 = 38,660 (Answer)
Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.1635 = 16.35% probability of a sample result with 68% or fewer returns prior to the third day.
In a normal distribution with mean 
and standard deviation 
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportions has mean
and standard error 
In this problem:
- Sample of 500 customers, hence
.
- Amazon believes that the proportion is of 70%, hence
The <u>mean and the standard error</u> are given by:
The probability is the <u>p-value of Z when X = 0.68</u>, hence:
By the Central Limit Theorem
has a p-value of 0.1635.
0.1635 = 16.35% probability of a sample result with 68% or fewer returns prior to the third day.
A similar problem is given at brainly.com/question/25735688
Answer: your answer will be (b) 0
hope it helps
