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Pachacha [2.7K]
3 years ago
10

Write the height of zak as a fraction of the height of fred

Mathematics
1 answer:
Assoli18 [71]3 years ago
7 0

\bf \cfrac{Zak}{Fred}\qquad \cfrac{1.86}{1.6}\implies \cfrac{~~\frac{186}{100}~~}{\frac{16}{10}}\implies \cfrac{186}{100}\cdot \cfrac{10}{16}\implies \cfrac{186}{16}\cdot \cfrac{10}{100}\implies \cfrac{93}{8}\cdot \cfrac{1}{10} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \cfrac{93}{80}~\hfill

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Solve the triangle. Round your answers to the nearest tenth.
sweet-ann [11.9K]

Answer:

  B.  m∠B = 118°, a = 17, c = 18

Step-by-step explanation:

The answer choices all agree on the values of ∠B and c, so we only need to compute the value of side a.

We can verify angle B is ...

  ∠B = 180° -30° -32° = 118°

By the law of sines, ...

  a/sin(A) = b/sin(B)

Multiplying by sin(A), we get ...

  a = b·sin(A)/sin(B) = 30·sin(30°)/sin(118°) ≈ 16.98855

  a ≈ 17.0 . . . units . . . . . matches choice B

__

If you like, you can also verify side c:

  c = b·sin(C)/sin(B) = 30·sin(32°)/sin(118°) ≈ 18.00512

  c ≈ 18.0 . . . units

5 0
3 years ago
Bro i will literally give u the brainliest for these
san4es73 [151]

Answer:

From the figure, it can be seen that ΔJ'K'L' is formed from ΔJKL by the rotation of ΔJKL by 90 degrees counter-clockwise.

It can also be seen that ΔJ"K"L" is obtained from ΔJ'K'L' by the refrection of ΔJ'K'L' across the x-axis.

Therefore, the rule that describes the composition of transformations that maps ΔJKL to ΔJ"K"L" is given by

Step-by-step explanation:

3 0
3 years ago
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zmey [24]
I’m gonna bet on D. Since I answered your question. Break my ankles✨
5 0
3 years ago
Read 2 more answers
Can anyone help me?
frozen [14]
       2x + x - 1               x
   =  ------------------ * ---------
          x(x - 1)               8

       3x - 1
=  --------------
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6 0
3 years ago
A small box of cereal contains 10 cups of cereal. A medium box of the same cereal contains 30% more cereal than the small box. H
mario62 [17]

Answer:

13 cups

Step-by-step explanation:

If the small box has 10 cups, then:

<u> (small) </u>     <u> 10 cups </u>   =  <u> 100% </u>

(medium)    x cups     =   130%

Now, cross multiply:

10 (130) = x (100)

1300 = 100x

x = 13

Another way to solve this is by turning 30% into a decimal:

30/100 = 0.3

10 (0.3) = 3

Now you have 30% of the 10 cups, but you need <u>30% more</u><em> </em>than the small box, so:

10 + 3 = 13 cups

6 0
3 years ago
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