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3 years ago

How do decantation and filtration differ which should be faster

1 answer:

8 0

Decantation describes when a substance settles to the bottom, think of the Hershey syrup and milk, the syrup slowly settles to the bottom. Filtration describes a mixture and as an example Sand and Water and separation comes from setting up a filter paper. Filtration is usually faster.

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12.Chlorine has 18 electrons. It is a(n) cation anion atom

emmasim [6.3K]

Answer:

chlorine is therefore an anion

4 0

3 years ago

Which statement best describes the pH of pure water?

Ray Of Light [21]

The pH of pure water is neutral because the concentration of hydronium ions equals that of hydroxide ions.

Answer: Option A

Explanation:

Water is one of the most important constituents of living being. It is said that there is no life without water. So that water need to neutral in nature to save life. Pure water is composed of hydronium $H^{+}$ and hydroxide $\left(O H^{-}\right)$ ions. It is known that hydronium ions are acidic in nature with concentration of $1 \times 10^{-7} \mathrm{M} / \mathrm{L}$ .

Similarly, the hydroxide ions which are basic in nature will be in same concentration as that of hydronium ions. So, as the concentration of basic and acidic elements are equal with the same strength of pH, the combination of these ions lead to formation of pure water with the pH being neutral.

7 0

3 years ago

Read 2 more answers

A weather balloon is filled with helium that occupies a volume of 5.57 104 L at 0.995 atm and 32.0°C. After it is released, it r

Alchen [17]

6.52 × 10⁴ L. (3 sig. fig.)

<h3>Explanation</h3>

Helium is a noble gas. The interaction between two helium molecules is rather weak, which makes the gas rather "ideal."

Consider the ideal gas law:

$P\cdot V = n\cdot R\cdot T$ ,

where

$P$ is the pressure of the gas,
$V$ is the volume of the gas,
$n$ is the number of gas particles in the gas,
$R$ is the ideal gas constant, and
$T$ is the absolute temperature of the gas in degrees Kelvins.

The question is asking for the final volume $V$ of the gas. Rearrange the ideal gas equation for volume:

$V = \dfrac{n \cdot R \cdot T}{P}$ .

Both the temperature of the gas, $T$ , and the pressure on the gas changed in this process. To find the new volume of the gas, change one variable at a time.

Start with the absolute temperature of the gas:

$T_0 = (32.0 + 273.15) \;\text{K} = 305.15\;\text{K}$ ,
$T_1 = (-14.5 + 273.15) \;\text{K} = 258.65\;\text{K}$ .

The volume of the gas is proportional to its temperature if both $n$ and $P$ stay constant.

$n$ won't change unless the balloon leaks, and
consider $P$ to be constant, for calculations that include $T$ .

$V_1 = V_0 \cdot \dfrac{T_1}{T_2} = 5.57\times 10^{4}\;\text{L}\times \dfrac{258.65\;\textbf{K}}{305.15\;\textbf{K}} = 4.72122\times 10^{4}\;\text{L}$ .

Now, keep the temperature at $T_1 =258.65\;\text{K}$ and change the pressure on the gas:

$P_1 = 0.995\;\text{atm}$ ,
$P_2 = 0.720\;\text{atm}$ .

The volume of the gas is proportional to the reciprocal of its absolute temperature $\dfrac{1}{T}$ if both $n$ and $T$ stays constant. In other words,

$V_2 = V_1 \cdot\dfrac{\dfrac{1}{P_2}}{\dfrac{1}{P_1}} = V_1\cdot\dfrac{P_1}{P_2} = 4.72122\times 10^{4}\;\text{L}\times\dfrac{0.995\;\text{atm}}{0.720\;\text{atm}}=6.52\times 10^{4}\;\text{L}$

(3 sig. fig. as in the question.).

See if you get the same result if you hold $T$ constant, change $P$ , and then move on to change $T$ .

6 0

3 years ago

A kayak travels in a lake at an average speed of 35 m/min. If the perimeter of the lake

DanielleElmas [232]

Answer: 4 hours

Explanation:

It takes the kayak 1 minute to travel 35 meters.

Divide the total (8400m) by the amount of meters per minute (35m)

$\frac{8400m}{35m} =240minutes$

Now convert into hours. (Remember that 1h has 60min)

$240min(\frac{1h}{60min})=4h$

6 0

3 years ago

A car is traveling at a speed of 95 mi/h. If there are 0.62137 miles (mi) in a kilometer,

SIZIF [17.4K]

Answer:

42 m/s

Explanation:

To we convert units for speed we can use dimensional analysis. First thing we do is seperate the measurement into a fraction. After this we can multiply by 1km over 0.62137 miles. We do this so that the miles cancel out.

$\frac{95mi}{h}$ × $\frac{1km}{0.62137mi}$ = $\frac{95km}{0.62137h}$

After this we can use a conversion factor and divide by 3.6.

$\frac{95km}{0.62137h}$ ÷ 3.6 = 42 m/s

4 0

3 years ago