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3 years ago

Which statement best describes the pH of pure water?

Chemistry

2 answers:

Ray Of Light [21]3 years ago

7 0

The pH of pure water is neutral because the concentration of hydronium ions equals that of hydroxide ions.

Answer: Option A

<u>Explanation:</u>

Water is one of the most important constituents of living being. It is said that there is no life without water. So that water need to neutral in nature to save life. Pure water is composed of hydronium $H^{+}$ and hydroxide $\left(O H^{-}\right)$ ions. It is known that hydronium ions are acidic in nature with concentration of $1 \times 10^{-7} \mathrm{M} / \mathrm{L}$ .

Similarly, the hydroxide ions which are basic in nature will be in same concentration as that of hydronium ions. So, as the concentration of basic and acidic elements are equal with the same strength of pH, the combination of these ions lead to formation of pure water with the pH being neutral.

GalinKa [24]3 years ago

5 0

Answer: is the first option (a)

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The combustion of 0.570 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera

torisob [31]

Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.570 g

Moles of benzoic acid = $\frac{0.570 g}{122.12 g/mol}=0.004667 mol$

Energy released by 0.004667 moles of benzoic acid on combustion:

$Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J$

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.053°C

$Q=C\times \Delta T$

$15,066.8 J=C\times 2.053^oC$

$C=7,338.92 J/^oC$

Glucose:

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

Moles of glucose = $\frac{2.900 g}{180.16 g/mol}=0.016097 mol$

Energy released by the 0.016097 moles of calorimeter combustion:

$Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J$

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

$Q'=C\times \Delta T'$

$44,749.1 J=7,338.92 J/^oC\times \Delta T'$

$\Delta T'=6.097^oC$

The temperature change from the combustion of the glucose is 6.097°C.

6 0

3 years ago

The product of alpha decay of the Nobelium isotope 259No is

Svet_ta [14]

Answer:

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Explanation:

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3 years ago

4,600,000,000,000 in scientific notation

BabaBlast [244]

4.6to the twelth power plus ten or something like that it has been a while since I have done the scientific notation but where ever you put in the number of zeros. is twelve

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3 years ago

0.5 kg or 0.5 lb which is a larger quantity

masha68 [24]

The correct answer is 0.5 kg If you whant me to explaine pls tell me

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3 years ago

How many mL of a 4% mass/volume Mg(NO3)2 solution would contain 1.2 grams of magnesium nitrate?

Phoenix [80]

4% mass / volume :

4 g ---------> 100 mL
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V = 1.2 * 100 / 4

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hope this helps!

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3 years ago