Define natural and artificial hazards? wrong and silly answer will be reported

Archimedes tells us the lifting power of a balloon (how much mass it can lift) is equal to the difference between the mass of th

Finger [1]

Answer:

the Balogna could carry 19 passengers if filled with Hydrogen.

the Balogna could carry 17 passengers if filled with Helium.

Explanation:

Given that:

the radius of the cylinder r = 4.0 cm

the height h = 40 m

the volume of the cylinder will be:

$V = \pi r^2 h$

V = π (4.0 m)² (40)

V = 2010.62 m³.

where the density of the air = 1.23 kg/m³

the mass of the displaced air = Volume V ×density of the air

= 2010.62 m³ × 1.23 kg/m³

= 2473.0626 kg

To calculate how many passengers the Balogna could carry if it were filled with hydrogen, we have the following:

We are given the density of H₂ to be = 0.090 kg/m³

Therefore, the mass of Helium in the balloon = Volume V × density of the hydrogen

= 2010.62 m³ × 0.090 kg/m³

= 180.9558 kg

The total mass of the balloon = mass of H₂ + mass of empty balloon.

The total mass of the balloon = (180.9558+ 750) kg

= 930.9558 kg

Now, the Mass difference = mass of the air displaced -total mass of the balloon.

the Mass difference = (2473.0626 - 930.9558 ) kg

the Mass difference = 1542.1068 kg

∴

number of persons = mass difference/ mass of passenger

the number of persons = 1542.1068 kg /80 (kg/person)

the number of persons = 19.27 persons

the number of passengers $\simeq$ 19 passengers.

To calculate how many passengers the Balogna could carry if it were filled with helium, we have the following:

We are given the density of Helium to be = 0.18 kg/m³

Therefore, the mass of Helium in the balloon = Volume V × density of the hydrogen

= 2010.62 m³ × 0.18 kg/m³

= 361.9116 kg

The total mass of the balloon = mass of Helium + mass of empty balloon.

The total mass of the balloon = (361.9116 + 750) kg

= 1111.9116 kg

Now, the Mass difference = mass of the air displaced -total mass of the balloon.

the Mass difference = (2473.0626 - 1111.9116 ) kg

the Mass difference = 1361.151 kg

∴

number of persons = mass difference/ mass of passenger

the number of persons = 1361.151 kg /80 (kg/person)

the number of persons = 17.01 persons

the number of passengers $\simeq$ 17 passengers.

7 0

3 years ago

PLEASE HELP ASAP

Mkey [24]

Answer:

Oxidation state of Al in reactant: 0 . In product: +3

Oxidation state of Cu in reactant: +2 . In product: 0

Oxidation state of N in reactant: +5 . In product: +5

Oxidation state of O in reactant: -2 . In product: -2

Explanation:

The balanced redox equation is the following:

2 Al(s) + 3 Cu(NO₃)₂(aq) → 3 Cu(s) + 2 Al(NO₃)₃(aq)

For aluminum (Al):

In reactants, it is in the metallic solid-state (Al(s)), so it is the pure element. Pure elements has an oxidation number equal to 0.

In products, it is combined with N and O and forms an ionic compound, which can dissociate into ions as follows:

Al(NO₃)₃ → Al³⁺ + 3 NO₃⁻

So, aluminum is a monoatomic ion, and its oxidation number is equal to the charge of the ion. Thus, the oxidation number is +3.

For copper (Cu):

In reactants, it is present as a nitrate salt. So, it dissociates into ions as follows:

Cu(NO₃)₂ → Cu²⁺ + 2 NO₃⁻

Since Cu is in the form of a monoatomic ion, its oxidation number is equal to the charge of the ion (+2).

In products, it is in the metallic solid form (pure element). Thus, the oxidation number is 0.

For nitrogen (N):

Both in reactants and products, N is present in the nitrate ion (NO₃⁻) which is derived from the nitric acid (HNO₃). The oxidation number is calculated from the addition of the oxidation numbers of N and O multiplied by their subscripts, which must be equal to the charge of the compound (-1):

(N x 1) + (O x 3) = -1

In oxide compounds, the oxygen atom has an oxidation number of -2. So, the oxidation number of O is -2 because it derives from an oxide (nitric acid is obtained from nitric oxide). Thus, we calculate the oxidation number of N:

N + (-2 x 3) = -1

N - 6 = -1

N = - 1 + 6 = +5

For oxygen (O):

Both in reactants and products, O is present in the nitrate ion (NO₃⁻) which is derived from the nitric acid (HNO₃).

As we saw previously, the oxidation number of O is -2 because it derives from an oxide (nitric acid is obtained from nitric oxide).

6 0

3 years ago

Can somebody help me please

djverab [1.8K]

Answer:

匿名のハック

Explana

あなたはオタクになります

5 0

2 years ago

Quick help!!

Flauer [41]

Answer:

The Similarities Between Mechanical Waves and Electromagnetic Waves. Some similarities between mechanical waves like sound and electromagnetic waves like light are: Both wave types are defined by their frequency. The higher the frequency, the less distance between successive crests of a wave (aka wavelength).

Explanation:

welcome!

8 0

3 years ago

What is the percent composition of C4H10? (4 points)

Marina CMI [18]

Answer:82.7% C and 17.3% H

Explanation:

C4 = 12.0107g/mol x 4 = 48.0428 g/mol

H10 = 1.00794 g/mol x 10 = 10.0794 g/mol

Molar Mass of Butane, C4H10 = 48.0428 g/mol + 10.0794 g/mol= 58.1222 g/mol

percent composition of Carbon is = ( mass of carbon contained in butane / molar mass of Butane) x 100

=(48.0428 /58.1222) x 100% = 0.8265 x 100

=82.65% =82.7% of Carbon.

Percent composition of Hydrogen = (mass of Hydrogen contained in Butane / molar mass of Butane )x 100

( 10.0794/58.122 ) x 100% =0.1734 x 100

= 17.3% OF Hydrogen.

6 0

3 years ago

Define natural and artificial hazards?wrong and silly answer will be reported​

Define natural and artificial hazards?wrong and silly answer will be reported