Answer:
All ions must a overall charge
Explanation:
Answer:
4+3=3+3+2
Explanation:
4Ni(oh)3+3pb(so4)2=3pb(oh)4+2Ni2(so4)3
AlPO4----> Al+3 + PO4-3
Ksp= [Al+3] x [PO4-3]= 9.84 x 10^-21
Ksp= (x) (x)= x^2
X^2= 9.84x10-21
x= 9.92 x 10^-11
The molar solubility is 9.92 x 10^-11
<u>Answer:</u> The correct answer is Option b.
<u>Explanation:</u>
The balanced equilibrium reaction for the ionization of calcium fluoride follows:

s 2s
The expression for solubility constant for this reaction will be:
![K_{sp}=[Ca^{2+}][F^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5BF%5E-%5D%5E2)
We are given:

Putting values in above equation, we get:

To calculate the solubility in g/L, we will multiply the calculated solubility with the molar mass of calcium fluoride:
Molar mass of calcium fluoride = 78 g/mol
Multiplying the solubility product, we get:

Hence, the correct answer is Option b.