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Natalija [7]
3 years ago
8

Which type of reaction occurs in the following equation?

Chemistry
1 answer:
Tems11 [23]3 years ago
3 0
The  type  of reaction  in  above reaction is refered  to  as a disproportionation  reaction .It sometimes  used  to describe  desymmetrizing  reaction.in the equation  above compounds  of  intermediate  oxidation  state  are  converted  to  two  different  compound,  that  is Clo3  ions  and  2cl-
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The common ion effect for ionic solids (salts) is to decrease the solubility of the ionic compound in water significantly. Expla
MrMuchimi

Answer:

Explanation has been given below.

Explanation:

Let's consider solubility equilibrium of an ionic insoluble compound e.g. BaSO_{4}

BaSO_{4}\rightleftharpoons Ba^{2+}+SO_{4}^{2-}

Equilibrium constant of this solubility equilibrium is represented in terms of solubility product (K_{sp}) which is expressed as-

K_{sp}=[Ba^{2+}][SO_{4}^{2-}]

Now, if we add an ionic salt e.g. Na_{2}SO_{4} with a common ion SO_{4}^{2-} then concentration of SO_{4}^{2-} increases.

But, at a constant temperature, K_{sp} is constant.

Therefore, to keep K_{sp} constant, excess amount of SO_{4}^{2-} will combine with free Ba^{2+} ion in solution and produce BaSO_{4}.

Hence, as a whole, solubility of BaSO_{4} decreases.

3 0
4 years ago
Which of the following statements about steroid hormones is true?
Len [333]

Answer:

B. They bind to carrier proteins in order to be transported in the blood to

their target cells.

Explanation:

Steroid hormones are belongs to the class of chemical compound called steroid. Steroid hormones are majorly secreted by three glands - ovaries, testes and adrenal cortex.

Steroid hormones are released in the blood and are allowed to bind to the specific carrier proteins such as corticosteroid-binding globulin and albumin which helps them to carry to the target cells for the functioning.

The steroid hormone binds to receptor proteins in the target cell and not in the plasma membrane

Hence, the correct answer is "B. They bind to carrier proteins in order to be transported in the blood to  their target cells."

8 0
3 years ago
Periodic table matching help plz
frosja888 [35]

Answer:

1. g

2. g

3. b

Only know the first 3

8 0
4 years ago
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Rn-222 has a half-life of 3.82 days. If 25.0 g of Radon-22 was originally present, approximately how many grams would be left af
horsena [70]

Answer:

Approximately 0.39 g or 0.4 g if you're rounding up

Explanation:

15/3.82 = 3.92

Let's round that up to 4

That means 15 days is around 4 half lives

4 half lives means 1/16 of the original mass will be left

25/16 = 0.390625

6 0
4 years ago
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balandron [24]
#48 might be (A) but in not for sure
3 0
4 years ago
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