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3 years ago

The atmospheric pressure of a cold winter day in NYC is 25.94 InHg. Calculate this value in Pa.

Chemistry

1 answer:

White raven [17]3 years ago

8 0

Answer:

25.94

Explanation:

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What is the correct interpretation of the mole ratios for the elements in

VLD [36.1K]

Answer:

6 moles of C atoms, 12 moles of H atoms and 6 moles of O atoms

Explanation:

A chemical formula represents the number of moles of atoms presents in 1 mole of the compound.

For example, for 1 mole:

CₐHₓ, you have a moles of carbon and x moles of hydrogen.

Thus, for the molecule:

C₆H₁₂O₆, you have 6 moles of C atoms, 12 moles of H atoms and 6 moles of O atoms

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2 years ago

A student pours 10.0 g of salt into a container of water and observes the amount of time it takes for the salt to dissolve. She

9966 [12]

Answer:

It will go faster each time because she is stirring therefore the water can get to the salt faster than it just sitting at the top

Explanation:

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2 years ago

What influences the movement of ions and molecules?

alexandr402 [8]

Energy helps the moving precess

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2 years ago

Read 2 more answers

Non metals whose 2 forms 1]very hard 2] conductor of electricity

Usimov [2.4K]

Answer:

Diamond

Explanation:

Diamond has covalent bonds, which makes it a non-metal.

However, it also has a tetrahedral structure, which holds its C atoms together by strong forces, thus making it hard.

Diamond also has free-moving electrons due to its tetrahedral structure, thus making it possible to conduct electricity.

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2 years ago

he equilibrium constant, Kc , for the following reaction is 7.00×10-5 at 673 K.NH4I(s) NH3(g) + HI(g)If an equilibrium mixture o

frosja888 [35]

Answer: The number of moles of HI in the solution is $1.24\times 10{-3}$ moles.

Explanation:

We are given:

$K_c=7.00\times 10^{-5}\\n_{NH_3}=0.405mol\\n_{NH_4I}=1.45mol\\V=4.90L$

To calculate the concentration of a substance, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ ......(1)

Concentration of ammonia:

$[NH_3]=\frac{0.405mol}{4.90L}=0.083mol/L$

Concentration of ammonium iodide:

$[NH_4I]=\frac{1.45mol}{4.90L}=0.30mol/L$

For the given chemical reaction:

$NH_4I(s)\rightleftharpoons NH_3(g)+HI(g)$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[HI][NH_3]}{[NH_4I]}$

Putting values in above equation, we get:

$7.0\times 10^{-5}=\frac{[HI]\times 0.083}{0.30}$

$[HI]=2.53\times 10^{-4}$

Calculating the moles of hydrogen iodide by using equation 1, we get:

$2.53\times 10^{-5}=\frac{\text{Moles of HI}}{4.9}\\\\\text{Moles of HI}=1.24\times 10^{-3}$

Hence, the number of moles of HI in the solution is $1.24\times 10{-3}$ moles.

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2 years ago