It's D. Gravity holds everything in place
For simplicity, assume that the total mass of the compound is 100 g.
Therefore, by mass
Ca = 24.7 g, H = 1.2 g, C = 14.8 g, and O = 59.3 g
Converting these to moles
Mol = mass*1/atomic mass
Ca = 24.7*1/40.078 =0.6163 mol Ca
H = 1.2*1/1.01 = 1.1881 mol H
C = 14.8*1/12.01 = 1.2323 mol C
O = 59.3/16 = 3.7062 mol O
Next, divide all the mols by the smallest value obtained.
Ca: 0.6163/0.6163 = 1 mol Ca
H: 1.1881/0.6163 = 2 mol H
C: 1.2323/0.6163 = 2mol C
O: 3.7062/0.6163 = 6 mol O
Therefore, empirical formula of the compound is
CaH2C2O6
This compound is referred to as Calcium Bicarbonate
Answer:
6400 W (or) 6.4 KW
Explanation:
Formula we use,
→ P = I²R
Let's solve for the power of device,
→ P = I²R
→ P = (8)² × 100
→ P = 64 × 100
→ [ P = 6400 W ]
Hence, the power is 6400 W.