6000 kg train moving 5 m/sec to east collides with 5000 kg train moving 3 m/sec to west. What is their velocity
1 answer:
The final velocity is 1.37 m/s east
Explanation:
We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the two trains must be conserved before and after the collision.
So we can write:
where:
is the mass of the first train
is the initial velocity of the first train (we take east as positive direction)
is the mass of the second train
is the initial velocity of the second train
is the final combined velocity of the two trains
Re-arranging the equation and substituting the values, we find:
And the positive sign indicates their final direction is east.
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Answer : The average speed of the sprinter is, 34.95 Km/hr
Solution :
Average velocity : It is defined as the distance traveled by the time taken.
Formula used for average velocity :
where,
= average velocity
d = distance traveled = 200 m
t = time taken = 20.6 s
Now put all the given values in the above formula, we get the average velocity of the sprinter.
conversion :
(1 Km = 1000m)
(1 hr = 3600 s)
Therefore, the average speed of the sprinter is, 34.95 Km/hr
The displacement of Itzel according to the question is 6.3 miles SW
Displacement is defined as the distance moved by a body in a specified direction
Find the diagram attached
From the diagram given, we can see that AB is the displacement
To get the length AB, we will have to use the Pythagoras theorem:
From the diagram, we can also se that the direction of the displacement in the South West direction.
Hence the displacement of Itzel according to the question is 6.3 miles SW
Learn more here: brainly.com/question/19108075
