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katen-ka-za [31]
3 years ago
10

Find the product of 30−−√ and 610−−√. Express it in standard form (i.

Physics
2 answers:
mixer [17]3 years ago
5 0

The product of \sqrt{30} and 6\sqrt{10} in the standard form is \boxed{60\sqrt3} and the value of a and b are 60 and 3 respectively.

Explanation:

The product of the number in the square root is done by factorizing the number such that the product of the two same number inside the root can be written as the single number.

The mathematical expression for the product of the two same numbers inside a root is as shown:

\begin{aligned}\sqrt{a}.\sqrt{a}&=(\sqrt{a})^2\\&=a\end{aligned}

Similarly, the product of the two numbers \sqrt{30} and 6\sqrt{10} can also be taken by factorizing the number in a proper manner.

Factorize the number \sqrt{30} to its simplest form.

\begin{aligned}\sqrt{30}=\sqrt{3\times10}\\=\sqrt{3}.\sqrt{10}\end{aligned}

The two number can now be multiplied as shown below:

\begin{aligned}\sqrt{30}\times6\sqrt{10}&=\sqrt{3}.\sqrt{10}\times6\sqrt{10}\\&=\sqrt{3}\times(10\times6)\\&=60\sqrt{3}\end{aligned}

Compare the value of the product to the standard form a\sqrt{b}.

a\sqrt{b}=60\sqrt{3}\\a=60, b=3

Thus, the product of \sqrt{30} and 6\sqrt{10} in the standard form is \boxed{60\sqrt3} and the value of a and b are 60 and 3 respectively.

Learn More:

1. what type of mirror do dentist use brainly.com/question/997618

2. the amount of kinetic energy an object has depends on its brainly.com/question/137098

3. Unit of the rotational velocity is brainly.com/question/2887706

Answer Details:

Grade: Junior school

Subject: Physics

Chapter: Products and addition

Keywords:

product, square root, 6 root 10, root 30, standard form, values of a and b, separated, comma, followed by.

Helen [10]3 years ago
4 0
The product of √30 and √610 is 10√183.


√30  = √(2×3×5)
and √610 = √(2×5×61

Since 61 can't be factorised further.
Therefore, the value of √30×√610 is
= √(2×3×5×2×5×61)
= 2×5×√(3×61)
=10√183
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Answer: Partial pressure of nitrogen and xenon are 288mmHg and 548 mmHg respectively.

Explanation:

The partial pressure of a gas is given by Raoult's law, which is:

p_A=p_T\times \chi_A

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p_A = partial pressure of substance A

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m_{N_2}=2.80g

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\chi_{N_2}=\frac{\frac{m_{N_2}}{M_{N_2}}}{(\frac{m_{N_2}}{M_{N_2}}+\frac{m_{Xe}}{M_{Xe}})}

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Putting values in above equation, we get:

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Thus partial pressure of nitrogen and xenon are 288mmHg and 548 mmHg respectively.

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