What is the power through a device with a resistance of 100 ohms if a current of 8 A is running through it?
1 answer:
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Answer:
The induced voltage in the Secondary is 18 volt.
Explanation:
Given that,
Voltage = 120 volt
Number of turns in primary = 500
Number of turns in secondary = 75
We need to calculate the induced voltage in the Secondary
Using relation number of turns and voltage in primary and secondary
Where, = Number of primary coil
= Number of secondary coil
= Voltage of primary coil
= Voltage of primary coil
Put the value into the formula
Hence, The induced voltage in the Secondary is 18 volt.
Answer:
ΔS = - k ln (3)
Explanation:
Using the Boltzmann's expression of entropy, we have;
S = k ln Ω
Where;
S = Entropy
Ω = Multiplicity
From the question, the configuration of the molecules in a gas changes so that the multiplicity is reduced to one-third its previous value. This also causes a change in the entropy of the gas as follows;
ΔS = k ln (ΔΩ)
ΔS = kln(Ω₂) - kln(Ω₁)
ΔS = kln(Ω₂ / Ω₁) -------------(i)
Where;
Ω₂ = Final/Current value of the multiplicity
Ω₁ = Initial/Previous value of the multiplicity
Ω₂ = Ω₁ [since the multiplicity is reduced to one-third of the previous value]
Substitute these values into equation (i) as follows;
ΔS = k ln ( Ω₁ / Ω₁)
ΔS = k ln ()
ΔS = k ln (3⁻¹)
ΔS = - k ln (3)
Therefore, the entropy changes by - k ln (3)