If the 10 is being multiplied it’s 90
Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
Philip equation
ordered data: 3o(oranges), 3g(green), 6y, 8r, 13b(black, 15b(blue
mean: 8 mode: 3 range: 12
Step-by-step explanation:
First, let's move the 
to the right-hand side so we can determine what constant we'll need on the left-hand side to complete the square:
From here, since the coefficient of the 
term is 
, we know the square will be 
(since 
it's half of ).
To complete this square, we will need to add 
to both sides of the equation:
Now we can take the square root of both sides to figure out the solutions to :
Total of 2.7. ---Anna had 0.5 Sam 0.75 Michelle 0.45 and Paige 0.70
