An atm personal identification number (pin) consists of four digits, each a 0, 1, 2, . . . 8, or 9, in succession.
a. How many different possible pins are there if there are no restrictions on the choice of digits?
Solution: The are total 10 numbers between 0 and 9.
Also there are no restrictions on the choice of digits. Therefore, the possible number of different PINs is:
Therefore, there are 10,000 different possibles PINs.
Answer:
2nd option because the number next to the x is the slope (3) and the added number is your intercept (4)
Step-by-step explanation:
Your answer is: −4(x−3)(3x+1)
36% because 65 is nearer to the whole number
Answer:
<u>Step-by-step explanation:96 in the fourth since they are adding the answer itself two times before you get the other like 12 bacteria and then 24 so that means 12 + 12 is 24 and the third one 48 so 24 +24 =48</u>
fourth 48 + 48=96
fifth 96+96=192
sixth 192+192=384
seventh 384+384=768
last but not least 768+768 = 1536
so your answer is 1,536
