Please help me find the median to this problem

What is the slope of the line?

SVEN [57.7K]

-1/2 or 1/2

use the formula

y²-y¹ over x²-x¹

6 0

3 years ago

They Yankees won 90 of their 162 games last season. What percent of the games did they win?

LUCKY_DIMON [66]

Answer:

55.6%

Step-by-step explanation:

The fraction 90/162 in its decimal equivalent is 0. 556. Multiplying this by 100 yields the percentage 55.6%.

5 0

3 years ago

Read 2 more answers

Find the exact values of the remaining five trigonometric functions of o satisfying the given conditions.

Lyrx [107]

First, tan(θ) = sin(θ) / cos(θ), so if cos(θ) = 3/5 > 0 and tan(θ) < 0, then it follows that sin(θ) < 0.

Recall the Pythagorean identity:

sin²(θ) + cos²(θ) = 1

Then

sin(θ) = -√(1 - cos²(θ)) = -4/5

and so

tan(θ) = (-4/5) / (3/5) = -4/3

The remaining trig ratios are just reciprocals of the ones found already:

sec(θ) = 1/cos(θ) = 5/3

csc(θ) = 1/sin(θ) = -5/4

cot(θ) = 1/tan(θ) = -3/4

4 0

3 years ago

The Frill family and the Smith family go to the movies.

Sati [7]

Step-by-step explanation:

Let a be the price of 1 adult ticket.

Let c be the price of 1 child ticket.

given,

$6a + 2c = 124$

as equation 1,

and

$3a + 5c = 100$

as equation 2.

Now we will solve for a and c using elimination method of simultaneous equations.

Now we multiply equation 2 by 2 to eliminate a and solve for c.

$3a \times 2 + 5c \times 2 = 100 \times 2 \\ 6a + 10c = 200$

This new equation will be equation 3.

Now we will use equation 1 - equation 3 to eliminate a and solve for c.

$(6a - 6a) + (2c - 10c) = 124 - 200 \\ 0 + ( - 8c) = - 76 \\ - 8c = - 76 \\ c = - 76 \div - 8 \\ = 9.5$

Now substitute c into equation 2.

$3a + 5(9.5) = 100 \\ 3a + 47.5 = 100 \\ 3a = 100 - 47.5 \\ 3a = 52.5 \\ a = 52.5 \div 3 \\ = 17.5$

Therefore one adult ticket will cost $17.50 and one child ticket will cost $9.50.

7 0

3 years ago

Question 6 (1.25 points)

Lisa [10]

Answer:

Test statistic Z= 1.713

The calculated Z- value = 1.7130 < 2.576 at 0.01 level of significance

Null hypothesis is accepted

There is no difference between the mean annual salary of all lawyers in a city is different from $110,000

Step-by-step explanation:

Step(i):-

A researcher wants to test if the mean annual salary of all lawyers in a city is

different from $110,000

Mean of the Population μ = $110,000

Sample size 'n' = 53

Mean of the sample x⁻ = $114,000.

standard deviation of the Population = $17,000,

Level of significance = 0.01

Null hypothesis :

There is no difference between the mean annual salary of all lawyers in a city is different from $110,000

H₀: x⁻ = μ

Alternative Hypothesis : x⁻ ≠ μ

Step(ii):-

Test statistic

$Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{114000-110000}{\frac{17000}{\sqrt{53} } }$

Z = 1.7130

Tabulated value Z = 2.576 at 0.01 level of significance

The calculated Z- value = 1.7130 < 2.576 at 0.01 level of significance

Null hypothesis is accepted

There is no difference between the mean annual salary of all lawyers in a city is different from $110,000

4 0

3 years ago