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ser-zykov [4K]
4 years ago
9

NEED HELP WITH A MATH QUESTION

Mathematics
1 answer:
miv72 [106K]4 years ago
7 0

Answer:

(- 6, 6 )

Step-by-step explanation:

Assuming the centre of dilatation is the origin, then

The coordinates of the image points are 3 times the original points

B = (- 2, 2 ), then

B' = ( 3 × - 2, 3 × 2 ) = (- 6, 6 )

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Please solve the challenge problem J
Verdich [7]

Answer: (7x^2+144)/x^2

Step-by-step explanation:

f(h(x))=

f(12/x)=

(12/x)^2+7=

12^2/x^2 + 7=

144/x^2 +7=

144/x^2 +7*x^2/x^2=

144/x^2+7x^2/x^2=(7x^2+144)/x^2

6 0
2 years ago
2.According to www.city-data, the mean price for a detached house in Franklin County, OH in 2009 was $192,723. Suppose we know t
igor_vitrenko [27]

Answer:

0.7123 = 71.23% probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean price for a detached house in Franklin County, OH in 2009 was $192,723. Suppose we know that the standard deviation was $42,000.

This means that \mu = 192723, \sigma = 42000

Sample of 75:

This means that n = 75, s = \frac{42000}{\sqrt{75}}

What is the probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009?

1 subtracted by the p-value of Z when X = 190000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{190000 - 192723}{\frac{42000}{\sqrt{75}}}

Z = -0.56

Z = -0.56 has a p-value of 0.2877

1 - 0.2877 = 0.7123

0.7123 = 71.23% probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009.

5 0
3 years ago
A number between 67 and 113 that is a multiple of 4,6,and 8
Varvara68 [4.7K]
Well to solve this problem first you need to know the multiples of 4,6, and 8. Can you list them for me?

Then you find a number that is a multiple of all the numbers 4,6, and 8 that is in between 67 and 113.
3 0
3 years ago
Cheryl moves houses. Her old house is 3 kilometers from her new house. How many meters is it from the old house to the new house
d1i1m1o1n [39]

Answer:

3000 here hope this helps you out

3 0
3 years ago
An ant travels 75cm in 5 s. What was the ants speed
Reptile [31]

v =  \frac{75}{5} = 15 \frac{cm}{s}   \times  \frac{1m}{100cm}  = 0.15
3 0
3 years ago
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