Answer:
x = number of tickets sold for $26 = 3900 tickets
y = number of tickets sold for $40 = 2100 tickets
Step-by-step explanation:
A 6000-seat theater has tickets for sale at $26 and $40. How many tickets should be sold at each price for a sellout performance to generate a total revenue of $185,400?
Let
x = number of tickets sold for $26
y = number of tickets sold for $40
x + y = 6000
x = 6000 - y
$26 × x + $40 × y= $185, 400
26x + 40y = 185400
Substitute
26(6000 - y) + 40y = 185400
156000 - 26y + 40y = 185400
Collect like terms
- 26y + 40y = 185400 - 156000
14y = 29400
y = 29400/14
y = 2100 tickets
x = 6000 - y
x = 6000 - 2100
x = 3900 tickets
Hence
x = number of tickets sold for $26 = 3900 tickets
y = number of tickets sold for $40 = 2100 tickets
Answer:
I think u forgot to put a photo because I really don't understand
Step-by-step explanation:
not sure
Out of 120 students in exam, 2/3 of them passed. How many students passed?
now,
no of students passed = 2/3×120
= 0.66×120
=80...
therefore <em>8</em><em>0</em><em> </em><em> </em><em>students</em><em> </em><em>were</em><em> </em><em>passed</em><em>.</em><em>.</em><em>.</em><em>.</em>
6/8. multiply 3/4 by 2 and there is your answer.
