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Vikentia [17]
3 years ago
5

Write the equation of a line that goes through point (0,-8) has a slope of 0

Mathematics
2 answers:
Elena L [17]3 years ago
6 0

The equation of a line that goes through point (0,-8) has a slope of 0 is \bold{y=-8}

<u>Solution:</u>

Given, the slope of line passing through (0, -8) is 0

Point- slope form of a line is y - y_1 = m (x - x_1)

where m is the slope; y_1= -8 \text{ and } x_1= 0

On substituting the values we get,

y-(-8)=0\times x-0 \rightarrow y+8=0

\bold{\Rightarrow y=-8}

Thus, the required equation is y=-8

Slope:

The slope of a line is a number that measures its "steepness", usually denoted by the letter m. It is the change in y for a unit change in x along the line.

Deffense [45]3 years ago
5 0

Answer:

y = x - 8

Step-by-step explanation:

In the equation for slope, y = mx + b,

your slope being 0 makes the equation 'x' or 0x but x is preffered.

Your why would be -8 because there is no x in the point and it is a negative number.

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1)

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Step-by-step explanation:

We want to write the equation of the line that passes through the points (7, -4) and (-1, 3) first in point-slope form and then in slope-intercept form.

1)

First and foremost, we will need to find the slope of the line. So, we can use the slope-formula:

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2)

Now, let's use the point-slope form:

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We will substitute -7/8 for our slope m. We will also use the point (7, -4) and this will be our (x₁, y₁). So, substituting these values yield:

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Finally, we want to convert this into slope-intercept form. So, let's solve for our y.

On the right, distribute:

y+4=-\frac{7}{8}x+\frac{49}{8}

Subtract 4 from both sides. Note that we can write 4 using a common denominator of 8, so 4 is 32/8. This yields:

y=-\frac{7}{8}x+\frac{49}{8}-\frac{32}{8}

Subtract. So, our slope-intercept equation is:

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