Answer:
The ball you want to submerge displaces the water occupied in the ball's volume. ... In water the concrete has a buoyancy pressure force equal to the displaced liquid's weight and weighs only 120 pounds until it reaches the surface.
Explanation:
13.5g
Explanation:
Given parameters:
Mass of Na = 10g
Mass of O₂ = 10g
Unknown:
Mass of products formed = ?
Balanced equation = ?
Solution:
The balanced chemical equation is shown below:
4Na + O₂ ⇒ 2Na₂O
In any reaction, the specie in short supply determines the extent of the reaction.
This reaction is not an exclusion. We need to first determine the specie in short supply and use it to estimate the amount of product since we have a 100% yield which signifies that all was used up.
let us convert to moles;
Number of moles of Na =
= 0.435mole
Number of moles of O₂ =
= 0.313mole
From the given equation;
4 moles of Na requires 1 mole of O₂;
0.435 moles of Na will require
= 0.11 moles
But the given amount O₂ is 0.313, this is an excess of 0.313 - 0.11 = 0.203moles
We see that Na is the limiting reagent;
4 moles of Na gives 2 mole of Na₂O
0.435 moles of Na will give
= 0.22 moles
Mass of Na₂O = number of moles x molar mass = 62 x 0.22 = 13.5g
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The number of sigma bonds = 5, and number of pi bonds = 3 in the given compound. Shown in attachment are the two Lewis structures of the compound with molecular formula C4H10. The two structures are the isomers of each other.
Butane is an alkane represented by C4H10. All the bonds in this situation are single bonds because this substance is an alkane. Two shared electrons are present in every bond.
Each carbon atom requires 8 electrons around it in order to follow the Octet Rule. The octet rule was completed by the hydrogen bonds, eliminating the need for the electron dots.
Straight-chained butane is the first structure. The y-chained isobutane is the second structure.
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Answer:
1. 6.116x1024 Molecules of H2O
2. 13400 L
3. 8.001x1024 Molecules of Mg3(PO4)2
4. 572 g.
5. 1.017x1025 Molecules of N2
6. 7.24 g
.7. 6980 g. of Al(OH)3
8. 3H2 + N2 => 2NH3
9. S8 + 8O2 => 8SO2
10. Ni(ClO3)2→ NiCl2 + 3O2
11. C2H4 + 3O2→ 2CO2 + 2H2O
12. 2KClO3→ 2KCl + 3O2
13. Cu(OH)2 + 2HC2H3O2→ Cu(C2H3O2)2 + 2H2O
14. C3H8 + 5O2→ 3CO2 + 4H2O
15. 191 g of CO
<span>4.53<span>x^<span>10^22</span></span></span>Simplifies to:<span>4.53x</span><span>=<span>4.53*x</span></span><span>=<span>4.53<span>x</span></span></span>